If a leap year is selected at random, what is the chance that it

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 Multiple Choice QuestionsMultiple Choice Questions

721.

A speaks truth in 75% of the cases and B in 80% of the cases. Then, the probability that their statements about an incident do not match, is

  • 720

  • 320

  • 27

  • 57


722.

Given below is the distribution of a random variable X
X = x 1 2 3 4
P(X = x) λ 2λ 3λ 4λ

If α = PX < 3 and β = PX > 2, then α : β = ?

  • 2 5

  • 3 4

  • 4 5

  • 3 7


723.

A bag P contains 5 white marbles and 3 black marbles. Four marbles are drawn at random from P and are put in an empty bag Q. If a marble drawn at random from Q is found to be black then the probability that all the three black marbles in P are transfered to the bag Q

  • 17

  • 67

  • 18

  • 78


724.

sech - 112 + csch - 1 - 1 = ?

  • 0

  • 2 + 1

  • 2

  • 2 - 1


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725.

There are 10 intermediate stations on a railway line between two particular stations. The number ofways that a train can be made to stop at 3 of these intermediate stations so that no two of these halting stations are consecutive is

  • 56

  • 20

  • 126

  • 120


726.

The number of different ways of preparing a garland using 6 distinct white roses and 5 distinct red roses such that no two red roses come together is

  • 21600

  • 43200

  • 86400

  • 151200


727.

Box I contains 30 cards numbered I to 30 and Box II contains 20 cards numbered 31 to 50. A box is selected at random and a card is drawn from it. The number on the card is found to be a non-prime number. The probability that the card was drawn from Box I is :

  • 23

  • 25

  • 817

  • 417


728.

Let Ec denote the complement of an event E. Let E1, E2 and E3 be any pairwise independent events withP(E1) > 0 and PE1  E2 E3 = 0 then E3c  E3cE1 is equal to

  • PE3c - PE2

  • PE3c - PE2c

  • PE3 - PEc

  • PE2C + PE3


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729.

Two families with three members each and one family with four members are to be seated in a row. In how many ways can they be seated so that the same family members are not separated ?

  • 2! 3! 4!

  • 3!(4!)3

  • 3! . 2 . (4!)

  • (3!)3 . (4!)


 Multiple Choice QuestionsShort Answer Type

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730. If a leap year is selected at random, what is the chance that it will contain 53 Tuesdays?


Leap year contains 366 days.
∴ there are 52 complete weeks and two days other. The following are the possibilities for these two ‘over’ days:
(i) Sunday and Monday (ii) Monday and Tuesday (iii) Tuesday and Wednesday
(iv) Wednesday and Thursday (v) Thursday and Friday (vi) Friday and Saturday (vii) Saturday and Sunday.
Now there will be 53 Tuesdays in a leap year when one of the two over days is a Tuesday.
∴  out of 7 possibilities, two are favourable to this event.
 therefore space space space required space probability space equals space 2 over 7.

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