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Probability

Short Answer Type

861.

Fatima and John appear in an interview for two vacancies in the same post. The probability of Fatima's selection is $1 over 7 space and space$ that of John's selection is $1 fifth.$ What is the probability that none of them will be selected.

80 Views

862. Arun and Tarun appear for an interview for two vacancies. The probability of Arun's selection is

1 third

and that of Tarun's selection is

1 fifth.

Find the probability that only one of them will be selected.

135 Views

863. Kamal and Monica appeared for an interview for two vacancies. The probability of Kamal’s selection is

1 third

and that of Monica’s selection is

4 over 5.

Find the probability that only one of them will be selected.

91 Views

864. Surjit and Sachdev appeared for an interview. The probability of their selection is

1 third space and space 1 over 6

respectively. Find the probability both selected.

93 Views

865. Surjit and Sachdev appeared for an interview. The probability of their selection is

1 third space and space 1 over 6

respectively. Find the probability only one of them selected.

89 Views

866. Surjit and Sachdev appeared for an interview. The probability of their selection is

1 third space and space 1 over 6

respectively. Find the probability neither of them selected.

90 Views

867. Balwant and Kulwant appeared for an interview. The probability of their selection is

1 third space and space 1 fifth

respectively. Find the probability both selected.

101 Views

868. Balwant and Kulwant appeared for an interview. The probability of their selection is $1 third space and space 1 fifth$ respectively. Find the probability only of them selected.

Let A : Balwant is selected
B : Kulwant is selected
$therefore space space space straight P left parenthesis straight A right parenthesis space equals space 1 third comma space space straight P left parenthesis straight B right parenthesis space equals 1 fifth$
P(only one is selected) = P('A and not B' or B' and not A')
= P (A and not B) + P(B and not A)
= P(A) P(not B) + P(B) P(not A)
= P(A) [1 - P(B)] + P(B) [1 - P(A)]
= $1 third open parentheses 1 minus 1 fifth close parentheses space plus space 1 fifth space open parentheses 1 minus 1 third close parentheses$
$equals space 1 third cross times 4 over 5 plus 1 fifth cross times 2 over 3 space equals 4 over 15 plus 2 over 15 equals 6 over 15 equals space 2 over 5$