Previous Year Papers

Download Solved Question Papers Free for Offline Practice and view Solutions Online.

Test Series

Take Zigya Full and Sectional Test Series. Time it out for real assessment and get your results instantly.

Test Yourself

Practice and master your preparation for a specific topic or chapter. Check you scores at the end of the test.

Probability

Long Answer Type

901. There are two bags I and II. Bag I contains 3 white and 2 red balls and Bag II contains 5 white and 4 red balls. One ball is drawn at random from one of the bags and is found to be red. Find the probability that it was drawn from bag II.

83 Views

902. There are two bags I and II. Bag I contains 4 white and 3 red balls and Bag II contains 6 white and 5 red balls. One ball is drawn at random from one of the bags and is found to be red. Find the probability that it was drawn from bag II.

74 Views

903. There are two bags I and II. Bag I contains 2 white and 4 red balls and Bag II contains 5 white and 3 red balls. One ball is drawn at random from one of the bags and is found to be red. Find the probability that it was drawn from bag II.

75 Views

904. Bag I contains 3 red and 4 black balls and bag II contains 4 red and 5 black balls. One ball is transferred from bag I to bag II, then a ball is drawn from bag II, the ball so drawn is found to be red in colour. Find the probability that the transferred ball is black.

158 Views

Short Answer Type

905. A bag contains 4 red and 4 black balls, another bag contains 2 red and 6 black balls. One of the two bags is selected at random and a ball is drawn from the bag which is found to be red. Find the probability that the ball is drawn from the first bag.

83 Views

906. Bag I contains 3 red and 4 black balls while another Bag II contains 5 red and 6 black balls. One ball is drawn at random from one of the bags and it is found to be red. Find the probability that it was drawn from Bag II.

85 Views

Long Answer Type

907. Of the students in a college, it is known that 60% reside in hostel and 40% are day scholars (not residing in hostel). Previous year results report that 30% of all students who residue in hostel attain A grade and 20% of day scholars attain A grade in their annua! examination. At the end of the year, one student is chosen at random from the college and he has an A grade, what is the probability that the student is a hostler?

98 Views

Short Answer Type

908. Bag A contains 2 white and 3 red balls and bag B contains 4 white and 5 red balls. One ball is drawn at random from one of the bags and it is found to be red. Find the probability that it was drawn from the bag B.

72 Views

Long Answer Type

909. In answering a question on a multiple choice test, a student either knows the answer or guesses. Let

3 over 4

be the probability that he knows the answer and

1 fourth

be the probability that he guesses. Assuming that a student who guesses at the answer will be correct with probability

1 fourth.

What is the probability that the student knows the answer given that he answered it correctly?

93 Views

910. A laboratory blood test is 99% effective in detecting a certain disease when it is in fact, present. However, the test also yields a false positive result for 0.5% of the healthy person tested (i.e. if a healthy person is tested, then, with probability 0.005, the test will imply he has the disease). If 0.1 percent of the population actually has the disease, what is the probability that a person has the disease given that his test result is positive?

Let E₁, E₂, E be the events
E₁ : ‘the person has the disease’
E₂: ‘the person is healthy’,
E : ‘test is positive’,
   $therefore space space space space straight P left parenthesis straight E subscript 1 right parenthesis space equals space 0.1 space equals space 1 over 10 space space and space straight P left parenthesis straight E subscript 2 right parenthesis space equals space 1 minus 1 over 10 equals 9 over 10$

   $straight P left parenthesis straight E space vertical line space straight E subscript 1 right parenthesis space equals space 99 over 100 space and space straight P left parenthesis straight E subscript 2 right parenthesis space equals space 0.005 space equals space 5 over 1000$

Required probability = $straight P left parenthesis straight E subscript 1 space vertical line space straight E right parenthesis space equals space fraction numerator straight P left parenthesis straight E subscript 1 right parenthesis thin space straight P left parenthesis straight E space vertical line space straight E subscript 1 right parenthesis over denominator straight P left parenthesis straight E subscript 1 right parenthesis thin space straight P left parenthesis straight E space vertical line space straight E subscript 1 right parenthesis space plus space straight P left parenthesis straight E subscript 2 right parenthesis space straight P left parenthesis straight E space vertical line space straight E subscript 2 right parenthesis end fraction$

(By Bare's Theorem)
$equals space fraction numerator begin display style 1 over 10 end style cross times begin display style 99 over 100 end style over denominator begin display style 1 over 10 end style cross times begin display style 99 over 100 end style plus begin display style 9 over 10 end style cross times begin display style 5 over 1000 end style end fraction space equals fraction numerator begin display style 99 over 1000 end style over denominator begin display style fraction numerator 990 plus 45 over denominator 10000 end fraction end style end fraction equals space 99 over 1000 cross times 10000 over 1035 space equals 22 over 23.$

90 Views