A number n is chosen at random from S = {1, 2, 3, ... , 50}. LetA

Previous Year Papers

Download Solved Question Papers Free for Offline Practice and view Solutions Online.

Test Series

Take Zigya Full and Sectional Test Series. Time it out for real assessment and get your results instantly.

Test Yourself

Practice and master your preparation for a specific topic or chapter. Check you scores at the end of the test.
Advertisement

 Multiple Choice QuestionsMultiple Choice Questions

691.

A random variate X takes the values 0, 1, 2, 3 and its mean is 1.3. If P(X = 3) = 2P(X = 1) and P(X = 2) = 0.3, then P(X = 0) is equal to :

  • 0.1

  • 0.2

  • 0.3

  • 0.4


692.

An unbiased coin is tossed to get 2 points forturning up a head and one point for the tail.If three unbiased coins are tossed simultaneously, then the probability of getting a total of odd number of points is

  • 12

  • 14

  • 18

  • 38


693.

Suppose E and F are two events of a random experiment. If the probability of occurrence of E is 1/5 and the probability of occurrence of F given E is 1/10, then the probability of non-occurrence of atleast one of the events E and F is

  • 118

  • 12

  • 4950

  • 150


694.

Six faces of an unbiased die are numbered with 2, 3, 5, 7, 11 and 13. If two such dice are thrown, then the probability that the sum on the upper most faces of the dice is an odd number is

  • 518

  • 536

  • 1318

  • 2536


Advertisement
695.

A person who tosses an unbiased coin gains two points for turning up a head and loses one point for a tail. If three coins are tossed and the total score X is observed, then the range of x is

  • {0, 3, 6}

  • {- 3, 0, 3}

  • {- 3, 0, 3, 6}

  • {- 3, 3, 6}


696.

A coin and six faced die, both unbiassed, are thrown simultaneously. The probability of getting a head on the coin and an odd number on the die, is

  • 12

  • 34

  • 14

  • 23


Advertisement

697.

A number n is chosen at random from S = {1, 2, 3, ... , 50}. LetA = {n ∈ S:n + 50/n > 27}, B={n ∈ S : n is a prime) and C = {n ∈ S : n is a square). Then,correct order of their probabilities is

  • P(A) < P(B) < P(C)

  • P(A) > P(B) > P(C)

  • P(B) < P(A) < P(C)

  • P(A) > P(C) > P(B)


B.

P(A) > P(B) > P(C)

Given that S = 1, 2, 3, ..., 50                   A = n  S : n + 50n > 27                       = n  S : n <2 or n  > 25                       = 1, 26, 27, ... ,50         nA = 26B = n  S : n is a prime    = 2, 3, 5, 7, 11, 13, 17, 19, 23, 29, 31, 37, 41, 43, 47         nB = 15C = n  S :  n is a square    = 1, 4, 9, 16, 25, 36, 49   nC = 7 PA = nAnS = 2650     PB = nBnS = 1550     PC = nCnS = 750 PA > PB > PC


Advertisement
698.

Box A contains 2 black and 3 red balls, while Box B contains 3 black and 4 red balls. Out of these two boxes one is selected at random; and the probability of choosing Box A is double that of Box B. If a red ball is drawn from the selected box, then the probability that it has come from Box B

  • 2141

  • 1031

  • 1231

  • 1341


Advertisement
699.

Seven balls are drawn simultaneously from a bag containing 5 white and 6 green balls. The probability of drawing 3 white and 4 green balls is :

  • 7C711

  • C35 + C46C711

  • C25 C26C711

  • C36 C45C711


700.

In a book of 500 pages, it is found that there are 250 typing errors. Assume that Poisson law holds for the number of errors per page. Then,the probability that a random sample of 2 pages will contain no error, is :

  • - 3

  • - 5

  • - 1

  • - 2


Advertisement