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We have, a = 2, b = – 3 and c = 1 Now, D = b 2 – 4ac = (– 3) 2 – 4(2) (1) = 9 – 8 = 1 Hence, Descriminant (D) = 1.

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We have,
a = 2, b = – 3 and c = 1
Now, D = b² – 4ac
= (– 3)² – 4(2) (1) = 9 – 8 = 1
Hence, Descriminant (D) = 1.

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