Let the digits at tens and units place of the number be x and y respectively. Then, Number = 10x + 7
It is given that,
⇒ 10x + y = 4(x + y)
and 10x + y = 3xy
⇒ 6x – 3y = 0 and 10x + y = 3y
⇒ y – 2x and 10x + y = 3xy
⇒ 10x + 2x = 3x X 2x
⇒ 6x2 – 12x = 0
⇒ 6x (x – 2) = 0
⇒ x = 0 or x = 2
Since the given number is a two-digit number. So, its tens digit cannot be zero.
∴ x = 2
⇒ y = 2 x 2 = 4 [∵ = 2x]
Hence,
required number = 10x+y = 10 x 2 + 4 = 24.1