Find the LCM and HCF of the following integers by applying the prime factorisation method :
12, 15 and 21
Since 96 = 2 × 2 × 2 × 2 × 2 × 3
= 2s × 3   and    404 = 2 × 2 × 101 = 22 × 101
∴ LCM = Product of each prime factor with highest power
= 2s × 3 × 101 = 9696
i.e., LCM (96, 404) = 9696
HCF Product of common prime factors with lowest powers
= 22Â = 4
We know that,
HCF (a. b) × LCM (a,b) = a × b
⇒ HCF (96, 404) × LMC (96, 404) = 96 × 404
⇒ LCM (96, 404)
Using prime factorization method, Find the LCM of
(i) 12, 15, 20, 27 (ii) 21, 28, 36, 45.