If the following f : R f is defined by :
(i) f(2) (ii) f(4) (iii) f(-1) (iv) f (-3)
(i) For x =2, we use domain
(ii) For x =4, we use domain x > 3
(iii) For x = -1, we use domain
(iv) For x = -3, we use domain x < -2
Let f and g be two functions defined by f(x) =
find (i) f +g (ii) g + f (iii) f - g (iv) g - f (v) gg (vi) gf
The relation f is defined by
and relation g is defined by
Explain, why f is a function and g is not.
If a ε R and the equation - 3(x-[x]2 + 2(x-[x] +a2 = 0(where,[x] denotes the greatest integer ≤ x) has no integral solution, then all possible value of lie in the interval
(-1,0) ∪ (0,1)
(1,2)
(-2,-1)
(-∞,-2) ∪ (2, ∞)