Let f and g be two functions defined by f(x) =
find (i) f +g (ii) g + f (iii) f - g (iv) g - f (v) gg (vi) gf
We have : f(x) =
and g (x) =
Here,
Thus,
Then the functions (i) to (vi) with domain D = [1, 2] are defined by :
(i) (f + g) (x) = f(x) + g(x) =
(ii) (g + f) (x) = g(x) + f(x) =
(iii) (f - g)(x) = f(x) - g(x) =
(iv) (g - f) (x) = g(x) - f(x) =
(v) (fg)(x) = f(x)g(x) =
(vi) (gf)(x) = g(x) f(x) =
The relation f is defined by
and relation g is defined by
Explain, why f is a function and g is not.
If a ε R and the equation - 3(x-[x]2 + 2(x-[x] +a2 = 0(where,[x] denotes the greatest integer ≤ x) has no integral solution, then all possible value of lie in the interval
(-1,0) ∪ (0,1)
(1,2)
(-2,-1)
(-∞,-2) ∪ (2, ∞)