The characteristic of sets {1, 4, 7 }, {2, 5, 8} and {3, 6, 9} is that difference between any two elements of these sets is a multiple of 3.
∴ (x,y) ∈ R1 ⇒ x – y is a multiple of 3
⇒ {x,y} ⊂ {1,4,7} or {x, y} ⊂ {2, 5, 8} or {x,y} ⊂ {3, 6, 9}
⇒ (x,y) ∈ R2.
Hence R1 ⊂ R2.
Similarly, { x, y} ∈ R2
⇒ {x, y}  ⊂ {1, 4, 7} or {x,y} ⊂ {2, 5, 8} or {x, y} ⊂ {3, 6, 9} ⇒ x – y is divisible by 3 ⇒ {x ,y} ∈ R1.
∴ R2 ⊂ R1.
Hence, R1Â = R2.
Let R be the relation in the set N given by R = {(a, b) : a = b – 2, b > 6}.
Choose the correct answer.
(A) (2. 4) ∈ R (B) (3, 8) ∈ R (C) (6,8) ∈ R (D)(8,7) ∈ RÂ
Let A = {1, 2, 3}. Then number of relations containing (1, 2) and (1, 3) which are reflexive and symmetric but not transitive is
(A) 1 Â Â Â (B) 2 Â Â Â (C) 3 Â Â Â (D) 4