Find whether each of the following numbers is a perfect square or not?
(i) 121 (ii) 55 (iii) 81
(iv) 49 (v) 69
(i) 121
∵ 121 - 1 = 120 85-13 = 72
120 - 3 = 117 72 - 15 = 57
117 - 5 = 112 54 - 17 = 40
112 - 7 = 105 40 - 19 = 21
105 - 9 = 96 21 - 21 = 0
96 - 11 = 85
i.e. 121 = 1+3+5+7+9+11+13+15+17+19+21. Thus , 121 is a perfact square.
(ii) 55
∵ 55 - 1 = 54 30 - 11 = 19
54 - 3 = 51 19 - 13 = 6
51 - 5 = 46 6 - 15 = -9
46 - 7 = 39
39 - 9 = 30
Since, 55 cannot be expressed as the sum of successive old numbers starting from 1.
∴ 55 is not a perfact square.
(iii) 81
Since, 81 - 1 = 80 56 - 11 = 45
80 - 3 = 77 45 - 13 = 32
77 - 5 = 72 32 - 15 = 17
72 - 7 = 65 17 - 17 = 0
65 - 9 =56
∴ 81 = 1+3+5+7+9+11+13+15+17
Thus, 81 is a perfact square.
(iv) 49
Since, 49 - 1 = 48
48 - 3 = 45
45 - 5 = 40
40 - 7 = 33
33 - 9 = 24
24 - 11 = 13
13 - 13 = 0
∴ 49 = 1+3+5+7+9+11+13
Thus, 69 is not a perfact square.
(v) 69
Since, 69 - 1 = 68 44 - 11 = 33
68 - 3 = 65 33 - 13 = 20
65 - 5 = 60 20 - 15 = 5
60 - 7 = 53 5 - 17 = 12
53 - 9 = 44
∴ 69 cannot be expressed as the sum of consecutive odd num numbers starting fron 1. Thus, 69 is not a perfect square.
Express the following as the sum of two consecutive integers.
(i) 212 (ii) 132 (iii) 112 (iv) 192
Do you think the reverse is also true, i.e. is the sum of any two consecutive positive integers is perfect square of a number? Give example to support your answer.
The difference between the squares of two consecutive natural numbers is equal to the sum of the two numbers.
Can you find the square of the following numbers using the above pattern?
(i) 66666672 (ii) 666666672
What will be the unit digit of the squares of the following numbers?
(i) 81 (ii) 272 (iii) 799 (iv) 3853 (v) 1234 (vi) 26387 (vii) 52698 (viii) 99880 (ix) 12796 (x) 55555
The following numbers are obviously not perfect squares. Give reason.
(i) 1057 (ii) 23453 (iii) 7928 (iv) 222222 (v) 64000 (vi) 89722 (vii) 222000 (viii) 505050
The squares of which of the following would be odd numbers?
(i) 431 (ii) 2826 (iii) 7779 (iv) 82004
Observe the following pattern and find the missing digits.
112 = 121
1012 = 10210
10012 = 1002001
1000012 = 1 ............. 2 ..............1
100000012 = ........................