100 surnames were randomly picked up from a local telephone dire

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 Multiple Choice QuestionsShort Answer Type

241.

The following table gives the distribution of the life-time of 400 new lamps.

Life-time (hrs.)

No. of lamps

1500-2000

14

2000-2500

56

2500-3000

60

3000-3500

86

3500-4000

74

4000-4500

62

4500-5000

48

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242.

100 surnames were randomly picked up from a local telephone directory and the frequency distribution of the number of letters in the English alphabets in the surnames was obtained as follows:

Number of letters

1-4

4-7

7-10

10-13

13-16

16-19

Number of surnames

6

30

40

16

4

4

Determine the median number of letters in the surnames. Find the mean number of letters in the surnames? Also, find the modal size of the surnames.


Number of letters

Number of surnames

Cumulative frequency

1-4

6

6

4-7

30

36

7-10

40

76

10-13

16

92

13-16

4

96

16-19

4

100

 

x = 100

 

We have n = 100, so  open parentheses straight n over 2 close parentheses th observation = 50th observation.

So, median lies in the group of 7-10.

i.e.                                     Median class = 7 - 10
Now, we have                      Median class = 70 - 10 l = 7, straight n over 2 equals 50, cf = 36, f = 40 and h =3
Now, substituting these values in the formula of median, we get

Median space equals space space straight l plus open square brackets fraction numerator begin display style straight n over 2 end style minus cf over denominator straight f end fraction close square brackets space straight x space straight h space equals space 7 plus open square brackets fraction numerator 50 minus 36 over denominator 40 end fraction close square brackets space straight x 3 space equals space 7 plus 21 over 20 equals 7 plus 1.05 space equals space 8.05
Hence, the median number of letters in the surnames is 8.05.

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243.

The distribution below gives the weights of 30 students of a class. Find the Median weight of the students.

Weight (in k.g)

40-45

45-50

50-55

55-60

60-65

65-70

70-75

No. of students (f)

2

3

8

6

6

3

2

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244.

The following distribution gives the daily income of 50 workers of a factory.

Daily income (in Rs.)

100-120

120-140

140-160

160-180

180-200

Number of workers

12

14

8

6

10

Convert the distribution above to a less than type cumulative frequency distribution, and draw its ogive.

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 Multiple Choice QuestionsLong Answer Type

245.

Durine the medical check-up of 35 students of a class, their weight were recorded as follows:

Weight (in kg)

Number of students

Less than 38

0

Less than 40

3

Less than 42

5

Less than 44

9

Less than 46

14

Less than 48

28

Less than 50

32

Less than 52

35

During a less than type ogive for the given data. Hence obtain the median weight from the graph - and verify the result by using the formula.

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 Multiple Choice QuestionsShort Answer Type

246.

 The following table gives production yield per hectare of wheat of 100 farms of a village.

Production yield (in kg/ha)

50-55

55-60

60-65

65-70

70-75

75-80

Number of farms

2

8

12

24

38

16

Change the distribution to a more than type distribution and draw its ogive.

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247. A student draws a cumulative frequency curve for the marks obtained by 40 students of a class as shown below. Find the median marks obtained by the student of the class.


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248. Which measure of central tendency is given by the x-coordinate of the point of intersection of the 'more than ogive' and 'less than ogive'?
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249. Write the formula for finding the median for a gouped or continuous frequency distribution.
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250. What is the value of the median of the data using the graph in figure, of less than ogive and more than ogive?


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