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271.
Find the mean of the following frequency distribution.

Class-Interval

0-8

8-16

16-24

24-32

32-40

Frequency

8

10

15

9

8

Class-Interval (C.I.)	Frequency (f_i)	Class-mark (x_i)	(f_ix_i)
0 - 8	8	4	32
8 - 16	10	12	120
16 - 24	15	20	300
24 - 32	9	28	252
32 - 40	8	36	288
	Σf_i = 50		Σf_ix_i = 992

Now,

$top enclose X space equals space fraction numerator begin display style sum from blank to blank of end style f subscript i x subscript i over denominator begin display style sum from blank to blank of end style f subscript i end fraction equals 992 over 50 equals 19.84$

Hence, (he mean of frequency distriution is 19.84.

If the values of x or f are large, the calculation of mean by the direct method is quite lengthy and time consuming so, to minimize the time involved in calculation, we prefer assumed mean method.

111 Views

Long Answer Type

272.

Find the value of P, if the mean of the following distribution is 18.

x:	13	15	17	19	20 + p	23
f:	8	2	3	4	5p	6

1602 Views

Short Answer Type

273.

The following table shows markes scored by 140 students in a examinations.

Marks	0-10	10-20	20-30	30-40	40-50
No. of Sutdents	20	24	40	36	20

Calculate mean marks by using assumed mean method.

142 Views

274.

Find the mean of the following data

Class-lnterval	15-25	25-35	35-45	45-55	55-65
Frequency	60	35	22	18	15

139 Views

275.

The following table represents the wages of 50 workers in a factory.

Wages (in Rs.)	1450	1475	1500	1525	1550
No. of workers	12	13	7	10	8

Find the average wage of a workers.

108 Views

Long Answer Type

276.

The following table represents the expenditure on the usage of water by 70 families in a locality. Find the average expenditure per family.

Exp. water (in Rs.)	15-20	20-25	25-30	30-35	35-40	40-45	45-50	50-55
No. of families	7	8	7	8	10	15	7	8

101 Views

Short Answer Type

277.

The following table shows marks scored by 140 students in an examination.

Marks	0-10	10-20	20-30	30-40	40-50
No. of students	20	24	40	36	20

Calculate mean marks by Step Deviation Method.

332 Views

Long Answer Type

278.

The mean of the following frequency distribution is 62.8 and the sum of all frequencies is 50. Compute the missing frequency f₁ and f₂.

C.I.	0-20	20-40	40-60	60-80	80-100	100-120	Total
f	5	f₁	10	f₂	7	8	50

2780 Views

279.

The mean of the following frequency distribution is 132 and the sum of observations is 50. Find the missing frequency f₁ and f₂.

Class	0-40	40-80	80-120	120-160	160-200	200-240
Freq.	4	7	f₁	12	f₂	9

1145 Views

280.

The mean of the following frequency table is 53. But the frequencies f₁ and f₂ in the classes 20-40 and 60-80 arc missing. Find the missing frequencies.