The mean of the following frequency distribution is 132 and the
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    Multiple Choice QuestionsShort Answer Type

    271.

    Find the mean of the following frequency distribution.

    Class-Interval

    0-8

    8-16

    16-24

    24-32

    32-40

    Frequency

    8

    10

    15

    9

    8

     
    111 Views
    Answer

    Multiple Choice QuestionsLong Answer Type

    272.

    Find the value of P, if the mean of the following distribution is 18.

    x:

    13

    15

    17

    19

    20 + p

    23

    f:

    8

    2

    3

    4

    5p

    6 
    1602 Views
    Answer

    Multiple Choice QuestionsShort Answer Type

    273.

    The following table shows markes scored by 140 students in a examinations.

    Marks

    0-10

    10-20

    20-30

    30-40

    40-50

    No. of Sutdents

    20

    24

    40

    36

    20

     

    Calculate mean marks by using assumed mean method.
    142 Views
    Answer
    274.

    Find the mean of the following data

    Class-lnterval

    15-25

    25-35

    35-45

    45-55

    55-65

    Frequency

    60

    35

    22

    18

    15
    139 Views
    Answer
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    275.

    The following table represents the wages of 50 workers in a factory.

    Wages (in Rs.)

    1450

    1475

    1500

    1525

    1550

    No. of workers

    12

    13

    7

    10

    8

    Find the average wage of a workers.
    108 Views
    Answer

    Multiple Choice QuestionsLong Answer Type

    276.

    The following table represents the expenditure on the usage of water by 70 families in a locality. Find the average expenditure per family.

    Exp. water (in Rs.)

    15-20

    20-25

    25-30

    30-35

    35-40

    40-45

    45-50

    50-55

    No. of families

    7

    8

    7

    8

    10

    15

    7

    8

     
    101 Views
    Answer

    Multiple Choice QuestionsShort Answer Type

    277.

    The following table shows marks scored by 140 students in an examination.

    Marks

    0-10

    10-20

    20-30

    30-40

    40-50

    No. of students

    20

    24

    40

    36

    20

    Calculate mean marks by Step Deviation Method.

    332 Views
    Answer

    Multiple Choice QuestionsLong Answer Type

    278.

    The mean of the following frequency distribution is 62.8 and the sum of all frequencies is 50. Compute the missing frequency f1 and f2.

    C.I.

    0-20

    20-40

    40-60

    60-80

    80-100

    100-120

    Total

    f

    5

    f1

    10

    f2

    7

    8

    50
    2780 Views
    Answer
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    279.

    The mean of the following frequency distribution is 132 and the sum of observations is 50. Find the missing frequency f1 and f2.

    Class

    0-40

    40-80

    80-120

    120-160

    160-200

    200-240

    Freq.

    4

    7

    f1

    12

    f2

    9

    Here, we have                      A (assumed mean) = 100

    Here, we have                     sum from blank to blank of f subscript i space equals space 50 comma space sum from blank to blank of f subscript i u subscript i space equals space 2 f subscript 2 space plus space 24 comma space A (assumed mean) = 100
                                              
                                              top enclose straight x space equals space 132 space a n d space h space equals space 40

    It is given that                      sum from blank to blank of f subscript i space equals space 50
    rightwards double arrow                           f1 + f2 + 32 = 50
    rightwards double arrow                              f1 + f3  = 18

    Now,                       top enclose straight x space equals space A plus fraction numerator begin display style sum from blank to blank of end style f subscript i u subscript i over denominator begin display style sum from blank to blank of end style f subscript i end fraction cross times h

    rightwards double arrow                       132 = 100 + fraction numerator 24 plus 2 straight f subscript 2 over denominator 50 end fraction cross times 40

    rightwards double arrow                        132 = 100 + fraction numerator 4 left parenthesis 2 straight f subscript 2 plus 24 right parenthesis over denominator 5 end fraction

    rightwards double arrow                       132 = fraction numerator 500 plus 8 straight f subscript 2 plus 96 over denominator 5 end fraction
    rightwards double arrow                    132 x 5 = 8f2 + 596
    rightwards double arrow                     660 = 8f2 + 596
    rightwards double arrow                      8f2  = 64
    rightwards double arrow                       f2 = 8
    Putting this value in (i), we get

                         straight f subscript 1 plus 8 space equals space 18
    rightwards double arrow                f1  = 10
    Hence.           f1 = 10,  f2 = 8


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    280.

    The mean of the following frequency table is 53. But the frequencies f1 and f2 in the classes 20-40 and 60-80 arc missing. Find the missing frequencies.   

    Age (in years)

    0-20

    20-40

    40-60

    60-80

    80-100

    Total

    Number of people

    15

    f1

    21

    f2

    17

    100
    3182 Views
    Answer
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