Short Answer TypeThe runs scored by two teams A and B on the first 74 balls in a cricket match are given below:
|
No. of balls |
Runs scored |
|
|
Team A |
Team B |
|
|
0–12 |
10 |
4 |
|
12–24 |
12 |
2 |
|
24–36 |
4 |
16 |
|
36–48 |
20 |
18 |
|
48–60 |
10 |
8 |
|
60–72 |
12 |
10 |
|
72–84 |
6 |
12 |
The distance (in 1 cm) covered by 30 cars in 2 hrs. are given below:
125, 107, 120, 90, 84, 100,
56, 140, 93, 149, 73, 68,
88,135,115,120,90,120,
136, 144, 104, 135, 60, 79
83, 100, 76,91,89, 120
Form a frequency distribution table (with tally works), one of the intervals being 100-120 (120 not included).
Find the mean of the following distribution:
|
Variable (x) |
Frequency (f) |
|
4 |
12 |
|
5 |
10 |
|
6 |
8 |
|
7 |
7 |
|
8 |
8 |
|
9 |
5 |
The following observations have been arranged in ascending order. If the median of the data in 65, find the value of x.
32, 35, 50, 51, x, x + 2, 73, 76, 83, 90
Find the value of p, if the mean of the following distribution is 7.5:
|
x |
y |
|
3 |
6 |
|
5 |
8 |
|
7 |
15 |
|
9 |
8 |
|
11 |
8 |
|
13 |
4 |
|
x |
y |
xy |
|
3 |
6 |
18 |
|
5 |
8 |
40 |
|
7 |
15 |
105 |
|
9 |
P |
9p |
|
11 |
8 |
88 |
|
13 |
4 |
52 |
|
Total |
p + 41 |
9p + 303 |
          
          
     2(9p + 303) = 15(p + 41)
      18p + 606 = 15p + 615
     18p - 15p = 615 - 606
      3p = 9
      
Marks secured by a group of 10 students are as follows:
16, 18, 29, 31, 20, 23, 26, 25, 32, 20
(i) Find the mean of the data,
(ii) If 32 is replaced by 23 in the data. find the new mean.
(iii)Â If each observation in the given data is increased by 5 marks, then what will be the mean?
(iv) If two students securing 16 and 32 leave the group, then find the mean of remaining 8 students.
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