The value of k for which the lines 7x - 8y + 5 = 0, 3x - 4y + 5 = 0 and 4x + 5y + k = 0 are concurrent, is given by
- 45
44
54
- 54
Equation of straight line passing through intersection of x + 5y + 7 = 0, 3x + 2y - 5 = 0 and perpendicularto 7x + 2y - 5 = 0, is
2x - 7y - 20 = 0
2x + 7y - 20 = 0
- 2x + 7y - 20 = 0
2x + 7y + 20 = 0
A.
2x - 7y - 20 = 0
The equations of given lines are
x + 5y + 7 = 0 ...(i)
and 3x + 2y - 5 = 0 ...(ii)
On solving Eqs. (i) and (ii), we get
x = 3, y = - 2
The point of intersection of lines (i) and (ii) is (3, - 2)
The equation of line perpendicular to
7x + 2y - 5 = 0 is
...(iii)
This line passes through the point (3, - 2).
The points situated on the line x + y = 4 whose distance fromthe line 4x + 3y = 10 is unity, are
(3, 1), (- 7, 11)
(3, 1), (7, 11)
(- 3, 11), (- 7, 11)
(1, 3), (- 7, 11)
Lines represented by the pair ofstraight lines ab (x2 - y2) +(a2 - b2)y = 0, are
ax - by = 0, bx + ay = 0
ax - by = 0, bx - ay = 0
ax + by = 0, bx + ay = 0
ax + by = 0, bx - ay = 0
The pair of straight lines joining the origin to the points of intersection of the line y = x + c and the circle x2 + y2 = 2, are at right angles, if
c2 - 4 = 0
c2 - 8 = 0
c2 - 9 = 0
c2 - 10 = 0
If the ratio of gradients ofthe lines represented by ax2 + 2hxy + by = 0 is 1 : 3, then the value of the ratio h2 : ab is
1 : 3
(1, 1)
4 : 3
1 : 1
If the equations of the opposite sides of a parallelogram are x2 - 7x + 6 = 0 and y2 - 14y + 40 = 0, then the equation of one of its diagonal will be
6x + 5y + 14 = 0
6x - 5y + 14 = 0
5x + 6y + 14 = 0
5x - 6y - 14 = 0