Three cubes of metal whose edges are 6 cm, 8 cm and 10 cm are melted and a new cube is made (i) Find the length of the edge of the new cube.
(ii) Find the total surface area of the new cube.
Let l, b and h are respectively the length, breadth and height of the cuboid, then
l = (12 + 12) cm = 24 cm
when two cubes are joined we get a cuboid b = 12 cm and h = 12 cm.
Now,
The Surface Area of the resulting cuboid
= 2 (lb + bh + hl) cm2
= 2 (24 x 12 + 12 x 12 + 24 x 12) cm2
= 2 (288 + 144 + 288) cm2
= 2 (720) cm2
= 1440 cm2.
Problems Based on Conversion of Solids from Shape to Another