If the radius of the base of a right circular cone is halved keeping the height same, what is the ratio of the volume of the reduced cone to that of the original one?
Let the base radii of the two right circular cones be 3x and 5x respectively.
Let their common height be h. Then,
Volume of the first cone (v1) =
and, volume of the second cone (v2) =
Ratio of their volumes