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394. A cylindrical tube opened at both ends is made of iron sheet which is 2 cm thick. If the outer diameter is 16 cm and its length is 100 cm, find how many cubic centimeters of iron has been used in making a tube?

open parentheses Use space straight pi space equals 22 over 7 close parentheses

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395. The water for a factory is stored in a hemispherical tank whose internal diameter is 14 m. The tank already contains 50 kiloliters of water. Water is pumped into the tank to fill its capacity. Calculate the volume of water pumped into the tank.

open parentheses Use space straight pi equals 22 over 7 close parentheses

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396. A match box measures 4 cm x 2.5 cm x 1.5 cm. What will be the volume of a packet containing 12 such boxes?

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397. Monica has a piece of canvas whose area is 818 m². She uses it to have a conical tent made, with a base radius of 10 m. Assuming that all the stitching margin and the wastage incurred while cutting amounts to approximately 1.6 nr, find the volume of the tent that can be made with it.

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398. A wall 4 m long, 3 m height and 13 cm thick is made up of bricks each measuring 20 cm x 12 cm x 6.5 cm. Find the number of bricks required to build the wall.

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399. Find the total surface area and volume of a hemisphere of radius

square root of 3

a units.

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400. A wooden bookshelf has external dimensions as follows: Height = 110 cm, Depth = 25 cm, Breadth = 85 cm (see figure). The thickness of the plank is 5 cm everywhere. The external faces are to be polished and the inner faces are to be painted. If the rate of polishing is 20 paise per cm² and the rate of painting is 10 paise per cm², find the total expenses required for polishing and painting the surface of the bookshelf.

Surface area to be polished = [(110 x 85) + 2(110 x 25) + 2(85 x 25) + 2(110 x 5) + 4(75 x 5)]
= (9350 + 5500 + 4250 + 1100 + 1500) cm² = 21700 cm²∴ Expenses required for polishing @ 20 paise per cm²= 21700 x 20 paise

$equals space straight र space fraction numerator 21700 cross times 20 over denominator 100 end fraction equals space straight र space 4340$

Surface area to be painted
= [2(20 x 90) + 6(75 x 20) + (75 x 90)]
= (3600 + 9000 + 6750) cm² = 19350 cm²∴ Expenses required for painting @ 10 paise per cm²= 19350 x 10 paise

$equals space straight र space fraction numerator 19350 cross times 10 over denominator 100 end fraction equals space straight र space 1935$