Find the coordinates of the point where the line through (5, 1,

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 Multiple Choice QuestionsShort Answer Type

51. Find a vector equation of the line through the points A (3, 4, – 7) and B (1, – 1, 6).
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52. Find the vector equation for the line passing through the points (– 1, 0, 2) and (3, 4, 6).
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53. Find the vector and cartesian equations of the line that passes through the origin and (5,- 2, 3).
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54. Find the vector and the cartesian equations of the line that passes through the points (3, – 2, – 5), (3, – 2, 6).
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55. Find the vector equation of line joining the points whose vectors are 2 space straight i with hat on top minus straight j with hat on top plus straight k with hat on top space space and space straight i with hat on top space plus space 2 space straight j with hat on top space minus space 3 space straight k with hat on top.
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56. If the points (–1, 3, 2), (– 4, 2, –2) and (5, 5, λ) are collinear, then find the value of λ.
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 Multiple Choice QuestionsLong Answer Type

57. Show that the points whose position vectors are given by 
2 space straight i with hat on top space plus space straight j with hat on top space plus space 3 space straight k with hat on top comma space space minus space 4 space straight i with hat on top space plus space 3 space straight j with hat on top space minus space straight k with hat on top comma space space 5 space straight i with hat on top space plus space 5 space straight k with hat on top are collinear. 
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 Multiple Choice QuestionsShort Answer Type

58.

Show that the point whose position vectors are given by negative 2 space straight i with hat on top space plus space 3 space straight j with hat on top space plus space 5 space straight k with hat on top comma space space straight i with hat on top space plus space 2 space straight j with hat on top space plus space 3 space straight k with hat on top space space and space space 7 straight i with hat on top space minus space straight k with hat on top are collinear. 

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 Multiple Choice QuestionsLong Answer Type

59. Find the coordinates of the point where the line through A(3, 4, 1) and B (5, 1, 6) crosses the x y-plane.
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60. Find the coordinates of the point where the line through (5, 1, 6) and (3, 4, 1) crosses the YZ-plane.


The line passes through (5, 1, 6) and (3, 4, 1)
∴   the equation of line is
              fraction numerator straight x minus 5 over denominator 3 minus 5 end fraction space equals space fraction numerator straight y minus 1 over denominator 4 minus 1 end fraction space equals fraction numerator straight z minus 6 over denominator 1 minus 6 end fraction

or          fraction numerator straight x minus 5 over denominator negative 2 end fraction space equals space fraction numerator straight y minus 1 over denominator 3 end fraction space equals space fraction numerator straight z minus 6 over denominator negative 5 end fraction

or        fraction numerator straight x minus 5 over denominator 2 end fraction space equals space fraction numerator straight y minus 1 over denominator negative 3 end fraction space equals space fraction numerator straight z minus 6 over denominator 5 end fraction                                           ...(1)

It meets yz-plane where x = 0
  ∴     putting x = 0 in (1), we get,

fraction numerator 0 minus 5 over denominator 2 end fraction space equals space fraction numerator straight y minus 1 over denominator negative 3 end fraction space equals space fraction numerator straight z minus 6 over denominator 5 end fraction

therefore space space space space space space space space space space minus 5 over 2 space equals space fraction numerator straight y minus 1 over denominator negative 3 end fraction space equals space fraction numerator straight z minus 6 over denominator 5 end fraction
therefore space space space space space space straight y minus 1 space equals space 15 over 2 comma space space straight z minus 6 space equals space minus 25 over 2
therefore space space space space space space space space space space space space space straight y space equals space 17 over 2 comma space space straight z space equals space minus 13 over 2
therefore space space space space point space is space open parentheses 0 comma space 17 over 2 comma space minus 13 over 2 close parentheses.
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