91.
Find the length of perpendicular from (2, 1, 3) on the line
![fraction numerator straight x minus 4 over denominator 5 end fraction space equals fraction numerator straight y minus 2 over denominator 4 end fraction space equals space fraction numerator straight z minus 3 over denominator 3 end fraction.](/application/zrc/images/qvar/MAEN12064541.png)
Let the given line AB be
![](/application/zrc/images/qvar/MAEN12064541-1.png)
![fraction numerator straight x minus 4 over denominator 5 end fraction space equals space fraction numerator straight y minus 2 over denominator 4 end fraction space equals space fraction numerator straight z minus 3 over denominator 3 end fraction](/application/zrc/images/qvar/MAEN12064541-2.png)
Any point M on this line is
(5 r + 4, 4 r + 2, 3 r + 3)
Let this point M be the foot of perpendicular from P(2, 1, 3) on AB.
Direction-ratios of PM are
5 r + 4 – 2, 4 r + 2 – 1, 3 r + 3 – 3 i.e. 5 r + 2, 4 r + 1, 3 r
Direction-ratios of AB are 5, 4, 3.
Since PM ⊥ AB
∴ (5 r – 2) (5) + (4 r + 1) (4) + (3 r) (3) = 0
∴ 25 r – 10 + 16 r + 4 + 9 r = 0
∴ required length of perpendicular = PM
![equals space square root of open parentheses 115 over 25 minus 2 close parentheses squared plus open parentheses 62 over 25 minus 1 close parentheses squared plus open parentheses 84 over 25 minus 3 close parentheses squared end root
equals space square root of open parentheses 65 over 25 close parentheses squared plus open parentheses 37 over 25 close parentheses squared plus open parentheses 9 over 25 close parentheses squared end root space equals space square root of 4245 over 625 plus 1369 over 625 plus 81 over 625 end root
equals space square root of 5675 over 625 end root space equals space square root of 227 over 25 end root space equals space fraction numerator square root of 227 over denominator 5 end fraction](/application/zrc/images/qvar/MAEN12064541-6.png)
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