Short Answer TypeEquation of any plane parallel to the plane – 2x + y– 3 z = 0 is –2x + y –3 z = k .... (1)
∴ it passes through P (1,4, - 2)
∴ –2 + 4 + 6 = k ⇒ k = 8
Putting k = 8 in (1), we get, – 2x + y–3 z = 8 which is the required equation.
Find equation of the plane parallel to x + 3y – 2z + 7 = 0 and passing through the origin.
Long Answer TypeShort Answer TypeIn each of the following cases, determine the direction cosines of the normal to the plane and the distance from the origin.
z = 2
In each of the following cases, determine the direction cosines of the normal to the plane and the distance from the origin.
x + y + z = 1
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