Find equation of the plane parallel to x + 3y – 2z + 7 = 0 and passing through the origin.
Equation of any plane parallel to the plane
3x – 2y + z – 11 = 0 is
3x - 2y + z + k = 0 ...(1)
∴ it passes through origin (0, 0, 0)
0 - 0 + 0 + k = 0 ⇒ k = 0
Putting k = 0 in (1), we get,
3x –2y + z = 0
which is required equation of plane.
In each of the following cases, determine the direction cosines of the normal to the plane and the distance from the origin.
z = 2
In each of the following cases, determine the direction cosines of the normal to the plane and the distance from the origin.
x + y + z = 1