If P (x, y, z) is a point on the line segment joning Q (2, 2, 4)

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 Multiple Choice QuestionsMultiple Choice Questions

421.

The area of a parallelogram with 3i^ + j^ - 2k^ and i^ - 3j^ + 4k^ as diagonal is :

  • 72

  • 73

  • 74

  • 75


422.

In a ABC, if 3 - 1a = 2b, A = 3B, then C is

  • 60°

  • 120°

  • 30°

  • 45°


423.

The x - axis, y - axis and a line passing through the point A (6, 0) from a ABC. If A = 30°, then the area of the , in sq unit is

  • 63

  • 123

  • 43

  • 83


424.

The mid point of the line joining the points (- 10, 8) and (- 6, 12)divides the line joining the points ( 4, - 2) and (- 2, 4) in the ratio

  • 1 : 2 internally

  • 1 : 2 externally

  • 2 : 1 internally

  • 2 : 1 externally


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425.

If from a point P (a, b, c) perpendiculars PA, PB are drawn to yz and zx planes, then the equation of the plane OAB is

  • bcx + cay + abz = 0

  • bcx + cay - abz = 0

  • bcx - cay + abz = 0

  • - bcx + cay + abz = 0


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426.

If P (x, y, z) is a point on the line segment joning Q (2, 2, 4) and R (3, 5, 6) such thatprojections of OP on the axes are 135, 195, 265 respectively, then P divides QR in the ratio

  • 1 : 2

  • 3 : 2

  • 2 : 3

  • 1 : 3


B.

3 : 2

Since, OP has projections 135, 195 and 265 on the coordinate axes, therefore

OP = 135i + 195j + 265k

Suppose, P divides the line joining Q(2, 2, 4) and R (3, 5, 6) in the ratio λ : 1.

Then, the position vector of P is

3λ + 2λ + 1i + 5λ + 2λ + 1j + 6λ + 4λ + 1k 135i + 195j + 265k = 3λ + 2λ + 1i + 5λ + 2λ + 1j + 6λ + 4λ + 1k   3λ + 2λ + 1 = 135,       5λ + 2λ + 1 = 195and 6λ + 4λ + 1 = 265           2λ = 3            λ = 32


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427.

The equation to the plane through the points (2, 3, 1) and ( 4, - 5 3) paralled to x - axis is

  • x + y + 4z = 7

  • x + 4z = 7

  • y - 4z = 7

  • y + 4z = 7


428.

The angle between r = (1 + 2µ)i +(2 + µ)j + (2µ - 1)k and the plane 3x - 2y + 6z = 0 (whereµ is a scalar) is

  • sin-11521

  • cos-11621

  • sin-11621

  • π2


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429.

The length of the shortest distance between the two lines r = (- 3i + 6j) + s (- 4i + 3j + 2k) and r = (- 2i + 7k) + t(- 4i + j + k) is

  • 7 unit

  • 13 unit

  • 8 unit

  • 9 unit


430.

The perpendicular distance of the point (6, 5, 8) from y-axis is

  • 5 unit

  • 6 unit

  • 8 unit

  • 10 unit


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