The equation of the plane passing through the origin and containing the line
is
x + 5y - 3z = 0
x - 5y + 3z = 0
x - 5y - 3z = 0
3x - 10y + 5z = 0
B.
x - 5y + 3z = 0
The equation of the plane through given line is
A(x - 1) + B(y - 2) + C(z - 3) = 0 ...(i)
Where A, B and C are the DR's of the normal to the plane.
Since, the straight line lie on the plane.
DR's of the plane is perpendicular to the line, i.e.,
5A + 4B + 5C = 0 ...(ii)
Since, it passes through (0, 0, 0), we get
- A - 2B - 3C = 0
A - 2B - 3C = 0 ...(iii)
On solving Eqs. (ii) and (iii), we get
From Eq. (i),
2(x - 1) - 10(y - 2) + 6(z - 3) = 0
2x - 2 - 10y + 20 + 6z - 18 = 0
2x - 10y + 6z = 0
x - 5y + 3z = 0
A flagpole stands on a building of height 450 ft and an observer on a level ground is 300 ft from the base of the building. The angle of elevation of the bottom of the flagpole is 30° and the height of the flagpole is SO ft. If 8 is the angle of elevation of the top of the flagpole, then tan is equal to
If A (0, 0), B (12, 0), C (12, 2), D (6, 7) and E (0, 5) are the vertices of the pentagon ABCDE, then its area in square units, is
58
60
61
63
The cartesian form of the plane is
2x - 5y - z - 15 = 0
2x - 5y + z - 15 = 0
2x - 5y - z + 15 = 0
2x + 5y - z + 15 = 0
Let P(- 7, 1, - 5) be a point on a plane and let O be the origin. If OP is normal to the plane, then the equation of the plane is
7x - y + 5z + 75 = 0
7x + y - 5z + 73 = 0
7x + y + 5z + 73 = 0
7x - y - 5z + 75 = 0
The shortest distance from the plane 12x + 4y + 3z = 327 to the sphere x2 + y2 + z2 + 4x - 2y - 6z = 155 is
26
13
39
The point in the xy-plane which is equidistant from the point (2, 0, 3), (0, 3, 2) and (0, 0, 1) is
(1, 2, 3)
(- 3, 2, 0)
(3, - 2, 0)
(3, 2, 0)