In Fig. (i) and (ii), DE || BC. Find EC in (i) and AD in (ii).

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179. In Fig. (i) and (ii), DE || BC. Find EC in (i) and AD in (ii).



(i)  In ∆ABC, we have
               space space DE parallel to BC
rightwards double arrow space space space space space space space space space space space space AD over DB equals AE over EC
             [By Basic proportionality therorem]
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(ii) In ∆ABC, we have
                     space space space space space DE parallel to BC
rightwards double arrow              space space AD over DB equals AE over EC
                  [By Basic proportionality theorem]
space space rightwards double arrow space space space space space space space space space space space space space space space space space space space fraction numerator AD over denominator 7.2 end fraction equals fraction numerator 1.8 over denominator 5.4 end fraction
space space rightwards double arrow space space space space space space space space space space space space space space space space space space space space space space space space space space AD space equals space fraction numerator 7.2 cross times 1.8 over denominator 5.4 end fraction equals 2.4 space cm.
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 Multiple Choice QuestionsLong Answer Type

180.

E and F are points on the sides PQ and PR respectively of a ∆PQR. For each of the following cases, state whether EF || QR:
(i) PE = 3.9 cm, EQ = 3 cm, PF = 3.6 cm and FR = 2.4 cm.
(ii) PE = 4 cm, QE = 4.5 cm. PF = 8 cm and RF = 9 cm.
(iii) PQ = 1.28 cm. PR = 2.56 cm, PE = 0.18 cm and PF = 0.36 cm.

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