∆ABC and ∆BDE are both equilateral triangles.
∴ ∆ABC ~ ∆BDE
[Using AAA similar condition].
We know that the ratio of the areas of two similar triangles is equal to the ratio of the squares of any two corresponding sides.
∴
Hence, (c) 4 : 1 is the correct option.
Sides of two similar triangles are in the ratio 4 : 9. Areas of these triangles are in the ratio
(a) 2 : 3 (b) 4 : 9
(c) 81 : 16 (d) 16 : 81.
In the given fig, ABD is a triangle right angled at A and AC ⊥ BD. Show that
(i) AB2 = BC .BD
(ii) AC2 = BC. DC
(iii) AD2 = BD . CD