A ladder 10 m long reaches a window 8 m above the ground. Find the distance of the foot of the ladder from base of the wall.
Two poles of heights 6 m and 11 m stand on a plane ground. If the distance between the feet of the poles is 12 m, find the distance between their tops.
Given: A triangle ABC in which AD ⊥ BC and DB = 3CD.
To prove: 2AB2 = 2AC2 + BC2
Proof: ∵ DB = 3CD [given]
Now, BC = CD + DB
BC = CD+ 3CD
BC = 4CD
Now, in right triangle ADB. we have
AB2 = AD2 + DB2
[Using Pythagoras Theorem]