333.Triangle ABC is right-angled at B and D is the mid-point of BC. Prove that AC2Â = 4AD2Â - 3AB2.
In right ∆ABC, by Pythagoras Theorem. AC2 = BC2 + AB2...(i) Similarly, in rt. ∆ABD, AD2 = BD2 + AB2         Â
                                             ...(ii) From (i) and (ii), we  get             Â
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334.In rhombus ABCD, prove that 4AB2Â = AC2Â + BD2.Â
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335.
In the given Fig., DE || BC, if   and AE = 4.8 cm, find EC.
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Long Answer Type
336.In the given figure, PQ || BC. If (i) Â Â Â Â (ii) Â Â Â Â
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337.If three or more parallel lines are intersected by two transversals. Prove that the intercepts made by them on the transversals are proportional.
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Short Answer Type
338.In quadrilateral ABCD, P is any point in side BC. PQ || AB and PR || BD. Show that QR is parallel to AD.
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339.If D and E are respectively, the points on the sides AB and AC of a triangle ABC, such that AD = 6 cm, BD = 9 cm, AE = 8 cm and EC = 12 cm then show that DE || BC.
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340.In a ∆ABC, D and E are points on sides AB and AC respectively such that BD = CE if ∠B = ∠C, show that DE || BC.