Previous Year Papers

Download Solved Question Papers Free for Offline Practice and view Solutions Online.

Test Series

Take Zigya Full and Sectional Test Series. Time it out for real assessment and get your results instantly.

Test Yourself

Practice and master your preparation for a specific topic or chapter. Check you scores at the end of the test.

Triangles

Short Answer Type

341.

In the given Fig., if EF || DC || AB. Prove that:
$AE over ED equals BF over FC$

112 Views

Long Answer Type

342. In the given Fig. PM is median of triangle PQR is the mid-point of PM and MN || QS.
Prove that: PS = SN = NR.

94 Views

343. The perimeters of two similar triangles are 25 cm and 15 cm respectively. If one side of the first triangle is 9 cm, find the corresponding side of the second triangle.

524 Views

344. Two poles of height a metres and b metres are p metres apart. Prove that the height of the point of intersection of the lines joining the top of each pole to the foot of the opposite pole is given by $fraction numerator ab over denominator straight a plus straight b end fraction metres.$

Solution not provided.

354 Views

345. Through the mid-point M of the side CD of a parallelogram ABCD, the line BM is drawn intersecting AC in 1 and AD produced to E. Prove that EL = 2 BL.

240 Views

Short Answer Type

346. Express x in terms of p, q and r.

91 Views

Long Answer Type

347. ABCD is a trapezium in which AB is parallel to DC. If AC and BD intersect at E and triangle AED is similar to triangle BEC. Prove that AD = BC.

723 Views

Short Answer Type

348.

In the given Fig. ∠CAB = 90° and AD is perpendicular to BC. If AC = 15 cm, AB = 20 cm and BD = 16 cm, find AD.

114 Views

Long Answer Type

349. In the given Fig; ∠EBA = ∠CDA = 90°, BC = 12 cm, CD = 18 cm, CE = (3x - 2) cm and AC = (4x + 2) cm.

Show that ∆ECB is similar to ∆ACD. Hence, find the lengths of segments CE and AC.

74 Views

350. In ∆ABC, AD ⊥ BC and BE ⊥ AC.
Prove:
(i) ∆ACD ~ ∆BCE.
(ii) AC × CE = BC × CD.

82 Views