Show that the direction cosines of a vector equally inclined to

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 Multiple Choice QuestionsShort Answer Type

91. Write the direction ratio’s of the vector straight a with rightwards arrow on top space equals space straight i with hat on top space plus space straight j with hat on top space minus space 2 space straight k with hat on top and hence calculate its direction cosines.
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92. Show that the direction cosines of a vector equally inclined to the axes OX, OY and OZ are fraction numerator 1 over denominator square root of 3 end fraction comma space fraction numerator 1 over denominator square root of 3 end fraction comma space fraction numerator 1 over denominator square root of 3 end fraction.


Let straight a with rightwards arrow on top space equals space straight a subscript 1 straight i with hat on top space plus space straight a subscript 2 straight j with hat on top space plus space straight a subscript 3 straight k with hat on top be the vector, where straight a subscript 1 comma space straight a subscript 2 comma space straight a subscript 3 are the direction ratios of the vector.
           Since vector is equally inclined to the axes

     therefore space space space space straight a subscript 1 space equals space straight a subscript 2 space equals space straight a subscript 3 space equals space straight p comma space space say.
therefore space space space straight a with rightwards arrow on top space equals space straight p space straight i with hat on top space plus space straight p space straight j with hat on top space plus straight p space straight k with hat on top
therefore space space space open vertical bar straight a with rightwards arrow on top close vertical bar space equals space square root of straight p squared plus straight p squared plus straight p squared end root space equals space square root of 3 space straight p squared end root space equals space square root of 3 space straight p
therefore space space space space space space space space space space space space space straight a with hat on top space equals space fraction numerator straight a with rightwards arrow on top over denominator open vertical bar straight a with rightwards arrow on top close vertical bar end fraction space equals space fraction numerator straight p over denominator square root of 3 space straight p end fraction straight i with hat on top space plus space fraction numerator straight p over denominator square root of 3 space straight p end fraction straight j with hat on top space plus space fraction numerator straight p over denominator square root of 3 space straight p end fraction straight k with hat on top
space space space space space space space space space space space space space space space space space space space space space equals space fraction numerator 1 over denominator square root of 3 end fraction straight i with hat on top space plus space fraction numerator 1 over denominator square root of 3 end fraction straight j with hat on top space plus space fraction numerator 1 over denominator square root of 3 end fraction straight k with hat on top
therefore   direction cosines of a vector equally inclined to axes are fraction numerator 1 over denominator square root of 3 end fraction comma space fraction numerator 1 over denominator square root of 3 end fraction comma space fraction numerator 1 over denominator square root of 3 end fraction.

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93.

If straight P with rightwards arrow on top left parenthesis 1 comma space 5 comma space 4 right parenthesis and straight Q with rightwards arrow on top space left parenthesis 4 comma space 1 comma space minus 2 right parenthesis, find the direction ratios of PQ with rightwards arrow on top.

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 Multiple Choice QuestionsLong Answer Type

94. If A (2, – 1, 3), B (8, 5, – 6) and C (4, 1, 0) are the vertices of a triangle. show that
(i) AB = 3 AC 
(ii) The direction-cosines of BC with rightwards arrow on top are fraction numerator negative 2 over denominator square root of 17 end fraction comma space fraction numerator negative 2 over denominator square root of 17 end fraction comma space fraction numerator 3 over denominator square root of 17 end fraction.

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 Multiple Choice QuestionsShort Answer Type

95. Show that vector straight i with hat on top space plus space straight j with hat on top space plus space straight k with hat on top is equally inclined to the axes OX. OY and OZ. 
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 Multiple Choice QuestionsLong Answer Type

96. Show that the points A (6. – 7, 0) B (16, – 19, – 4). C (0, 3, – 6), D (2, – 5, 10) are such that AB and CD intersect at the point P (1, – 1, 2).
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97. The vectors of magnitude a, 2a, 3a meet at a point and their directions arc. along the diagonals of three adjacent faces of a cube. Determine the magnitude of their resultant.
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 Multiple Choice QuestionsShort Answer Type

98. Write all the unit vectors in XY-plane.
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99. Write down a unit vector in XY-plane, making an angle of 30° with the positive direction of x-axis.
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 Multiple Choice QuestionsLong Answer Type

100. A girl walks 4 km towards west, then she walks 3 km in a direction 30° east of north and stops. Determine the girl’s displacement from her initial point of departure.
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