Prove, using vectors, that the altitudes of a triangle are concu

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 Multiple Choice QuestionsLong Answer Type

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231.

Prove, using vectors, that the altitudes of a triangle are concurrent.
OR
Prove that the perpendicular from the vertices to the opposite sides of a triangle are concurrent. 


Let ABC be given triangle and H be the point of intersection of altitudes AL and BM. Join CH and produce it to meet BA in N.
Take H as origin.

   Let straight a with rightwards arrow on top comma space straight b with rightwards arrow on top comma space stack straight c with rightwards arrow on top with rightwards arrow on top be the position vectors of A, B, C respectively.
therefore space space space space space HA with rightwards arrow on top space equals space straight a with rightwards arrow on top comma space space HB with rightwards arrow on top space equals space straight b with rightwards arrow on top comma space space HC with rightwards arrow on top space equals space straight c with rightwards arrow on top.
Since AL space perpendicular space BC
  therefore space space space space AH with rightwards arrow on top. space space BC with rightwards arrow on top space equals space 0
therefore space space space space minus straight a with rightwards arrow on top. space space left parenthesis straight c with rightwards arrow on top space minus space straight b with rightwards arrow on top right parenthesis space equals space 0
therefore space space space space space straight a with rightwards arrow on top. space straight b with rightwards arrow on top space minus space straight a with rightwards arrow on top. space space straight c with rightwards arrow on top space space equals space 0 space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space... left parenthesis 1 right parenthesis
Again,  BM perpendicular CA
therefore space space space space BH with rightwards arrow on top space. space CA with rightwards arrow on top space equals space 0
rightwards double arrow space space minus space stack straight b. with rightwards arrow on top space left parenthesis straight a with rightwards arrow on top space minus space straight c with rightwards arrow on top right parenthesis space equals space space 0 space space space space space space rightwards double arrow space space space space straight b with rightwards arrow on top. space straight c with rightwards arrow on top space minus space straight b with rightwards arrow on top. space straight a with rightwards arrow on top space equals space 0

rightwards double arrow space space space space space straight b with rightwards arrow on top. space straight c with rightwards arrow on top space minus space straight a with rightwards arrow on top. space straight b with rightwards arrow on top space equals space 0                                                   ...(2)
Adding (1) and (2), we get,
            straight b with rightwards arrow on top. space straight c with rightwards arrow on top space minus space straight a with rightwards arrow on top. space straight c with rightwards arrow on top space equals space space 0 space space space space space space space space rightwards double arrow space space space space left parenthesis straight b with rightwards arrow on top space minus space straight a with rightwards arrow on top right parenthesis. space straight c with rightwards arrow on top space equals space 0
rightwards double arrow space space minus space straight c with rightwards arrow on top. space thin space left parenthesis straight a with rightwards arrow on top space minus space stack straight b right parenthesis with rightwards arrow on top space equals space 0 space space space space rightwards double arrow space space space space CH with rightwards arrow on top. space space BA with rightwards arrow on top space equals space 0
rightwards double arrow space space space space space space CH space perpendicular space AB space space space space space space space space space space space space space space space space space rightwards double arrow space space space space CN thin space perpendicular space AB
therefore space space space space space space space space space space altitudes space of space increment ABC space meet space in space straight a space point space straight H.

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232. Show that the diagonals of a rhombus bisect each other at right angles.
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233. In a triangle OAB , ∠AOB = 90°. If P and Q are the points of trisection of AB, prove that OP squared space plus space OQ squared space equals space 5 over 9 AB squared
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234. In a tetrahedron, if two pairs of opposite edges are perpendicular, then the third pair is also perpendicular to each other and the sum of the sequares of two opposite edges is the same for each pair.
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235.

Find straight lambda space and space straight mu if  left parenthesis 2 space straight i with hat on top space plus space 6 space straight j with hat on top space plus space 27 space straight k with hat on top right parenthesis space cross times left parenthesis straight i with hat on top space cross times space straight lambda space straight j with hat on top space plus space straight mu space straight k with hat on top right parenthesis space equals space 0 with rightwards arrow on top.

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 Multiple Choice QuestionsShort Answer Type

236.

Find open vertical bar straight a with rightwards arrow on top space cross times space straight b with rightwards arrow on top close vertical bar comma space space space if space space straight a with rightwards arrow on top space equals space 2 space straight i with hat on top space plus straight j with hat on top space plus space 3 straight k with hat on top space and space straight b with rightwards arrow on top space equals space 3 space straight i with hat on top space plus space 5 space straight j with hat on top space minus space 2 space straight k with hat on top.

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237.

Find open vertical bar straight a with rightwards arrow on top space cross times space straight b with rightwards arrow on top close vertical bar  if  straight a with rightwards arrow on top space equals straight i with hat on top space minus space 7 space straight j with hat on top space plus space 7 space straight k with hat on top and straight b with rightwards arrow on top space equals space 3 straight i with hat on top space minus space 2 straight j with hat on top space plus space 2 straight k with hat on top

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238.

If straight a with rightwards arrow on top space equals space straight i with hat on top space plus space straight j with hat on top space minus space 3 space straight k with hat on top space and space straight b with rightwards arrow on top space equals 3 space straight i with hat on top space minus space 2 space straight j with hat on top space plus space 2 space straight k with hat on top comma space space find space open vertical bar 2 straight b with rightwards arrow on top cross times space straight a with rightwards arrow on top close vertical bar.

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 Multiple Choice QuestionsLong Answer Type

239.

If straight a with rightwards arrow on top space equals straight i with hat on top space minus straight j with hat on top space plus space 2 space straight k with hat on top comma space space straight b with rightwards arrow on top space equals space 2 space straight i with hat on top space minus space 3 space straight j with hat on top space minus space 4 space straight k with hat on top comma then show that straight a with rightwards arrow on top space cross times space straight b with rightwards arrow on top space equals space minus straight b with rightwards arrow on top space cross times space straight a with rightwards arrow on top

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 Multiple Choice QuestionsShort Answer Type

240. Find a unit vector perpendicular to both straight a with rightwards arrow on top space and space straight b with rightwards arrow on top if  straight a with rightwards arrow on top space equals space 4 space straight i with hat on top space plus space 3 space straight j with hat on top space plus space 2 space straight k with hat on top space space and space straight b with rightwards arrow on top space equals space 2 space straight i with hat on top space plus space 5 space straight j with hat on top space minus space 3 space straight k with hat on top

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