The central carbon atom of a free radical contains
6 electrons
7 electrons
8 electrons
10 electrons
Reaction for the formation of NaCl is
Na(g) + Cl2(g) → NaCl(s)
Na(s) + Cl2(g) → NaCl(s)
Na(g) + Cl2(g) → NaCl(s)
Na(g) + Cl2(g) → NaCl(g)
Which of the following species has highest bond energy?
O
O
O
O2
A.
O
i. O = KK' σ2s2, σ*2s2, σ2p,
Bond Order = = = 1
ii. O - KK' σ2s2, σ*2s2, σ2p,
Bond Order = = 2.5
iii. O - KK' σ2s2, σ*2s2, σ2p,
Bond Order = = 1.5
iv. O2 = KK' σ2s2, σ*2s2, σ2p,
Bond Order = = 2
Bond energy
Therefore, O has highest bond energy.