The shape of water molecule according to VSEPR theory, is
octahedral
distorted tetrahedral
trigonal planar
trigonal bipyramidal
XeF4 has a shape of
spherical
trigonal bipyramidal
square planar
tetrahedral
C.
square planar
XeF4 = 4 bp + 2 lp = sp3d2 hybridisation
Thus, the structure of XeF4 should be octahedral but its geometry becomes square planar due to the presence of two lone pairs of electrons as
In which of the following pairs both molecules do not possess same type of hybridisation?
CH4 and H2O
PCl5 and SF4
SF6 and XeF4
BCl3 and NCl3
If H-X bond length is 2.00 Å. and H-X bond has dipole moment 5.12 x 10-30 C-m, the percentage of ionic character in the molecule will be
100%
16%
18%
20%
(i) H—C—H angle in CH4
(ii) Cl—B—Cl angle in BCl3
(iii) F—I—F angle in IF7 in a plane
(iv) I—I—I angle in I
Increasing order of above bond angles is
(i) < (ii)< (iii)< (iv)
(ii)< (i) < (iii)< (iv)
(iii)< (i)< (ii)< (iv)
(iv)< (ii) < (i) < (iii)