Consider the formal charges on N and B in H3N-BF3 and indicate wh

Previous Year Papers

Download Solved Question Papers Free for Offline Practice and view Solutions Online.

Test Series

Take Zigya Full and Sectional Test Series. Time it out for real assessment and get your results instantly.

Test Yourself

Practice and master your preparation for a specific topic or chapter. Check you scores at the end of the test.
Advertisement

 Multiple Choice QuestionsMultiple Choice Questions

331.

The correct order of bond length is

  • b > a > c > d

  • a > b > c > d

  • d > c > b > a

  • c > d > b > a


332.

Consider the following ions:

(i) Ni2+   (ii) Co2+  (iii) Cr2+   (iv) Fe3+

(Given, at. no. Cr = 24, Fe = 26, Co = 27, Ni = 28)

The correct order of magnetic moment of these ions is

  • (i) < (ii) < (iii) < (iv)

  • (iv) < (ii) < (iii) < (i)

  • (i) < (iii) < (ii) < (iv)

  • (iii) < (iv) < (ii) < (i)


333.

Geometry of methyl free radical is

  • pyramidal

  • planar

  • tetrahedral

  • linear


334.

The electron configuration of the oxide ion is much most similar to the electron configuration of the

  • sulphide ion

  • nitride ion

  • oxygen atom

  • nitrogen atom


Advertisement
335.

Which substance has the greatest ionic character?

  • Cl2O

  • NCl3

  • PbCl2

  • BaCl2


336.

Favourable conditions for the formation of electrovalent bond is that the cation and anion must have, respectively

  • high ionisation potential and low electron affinity

  • low ionisation potential and high electron affinity

  • high ionisation potential and high electron affinity

  • low ionisation potential and low electron affinity


Advertisement

337.

Consider the formal charges on N and B in H3N-BF3 and indicate which of the following is true?

  • N is +ve and B is -ve

  • N is --ve and B is +ve

  • both N and B carry similar +ve or -ve charges

  • charge discrimination is difficult to make


A.

N is +ve and B is -ve

Formal charges on N and B in

 

Formal charge on N = Number of valence electrons - non-bonding electrons - 12 × boinding electrons.   = 5-0 -12×8= +1

Formal charge on B = 3 - 0 -12×8 =-1

Thus N is +ve and B is -ve.

 


Advertisement
338.

Consider (i) CO2 (ii) CCl(iii) C6Cl6 and (iv) CO and tell which of the following statements is correct?

  • (i), (ii) and (iii) only have zero dipole moment

  • (i), (ii) and (iv) only have zero dipole moment

  • only (iv) has zero dipole moment

  • All have zero dipole moment


Advertisement
339.

Intermolecular hydrogen bonding is strongest in

  • HCHO

  • CH3OH

  • C6H5OH

  • CH3NH2


340.

Which one of the following represents the correct state of hybridisation of P in PCl5 ?

  • s0p3

  • sp3d

  • s2p3

  • sp2d2


Advertisement