The pH of a 0.1 M solution of NH4OH (having Kb =1.0 x 10-5) is equal to
10
6
11
12
C.
11
The heat of neutralisation of a strong acid and a strong alkali is 57.0 kJ mol-1.The heat released when 0.5 mole of HNO3 solution is mixed with 0.2 mole of KOH is
57.0 kJ
11.4 kJ
28.5 kJ
34.9 kJ
Ammonium acetate which is 0.01 M, is hydrolysed to 0.001 M concentration. Calculate the change in pH in 0.001 M solution, if initially pH = pKa
5
10
100
1
An acid solution of pH = 6 is diluted 1000 times, the pH of the final solution becomes
6.01
9
3.5
6.99