In the reaction H2S+ H2O2 → S+ 2H2O
H2S is an acid and H2O2 is a base
H2S is a base and H2O2 is an acid
H2S is an oxidising agent and H2O2 is a reducing agent
H2S is an reducing agent and H2O2 is a oxidising agent
The solubility product (Ks) of the following compounds are given at 25°C
Compounds |
Ksp |
AgCl | 1.1 × 10-10 |
AgI | 1.0 × 10-16 |
PbCrO4 | 4.0 × 10-14 |
Ag2CO3 | 8.0 × 10-12 |
The most soluble and least soluble compounds are
AgCl and PbCrO4
AgI and Ag2CO3
AgCl and Ag2CO5
Ag2CO3 and AgI
Four moles of PCl5 are heated in a closed 4 dm3 container to reach equilibrium at 400 K. At equilibrium 50% of PCl5 is dissociated. What is the value of Kc for the dissociation of PCl5 into PCl3 and Cl2 at 400 K?
0.50
1.00
1.25
0.05
A weak monobasic acid is 1% ionized in 0.1 M solution at 25°C. The percentage of ionisation in its 0.025 M solution is
1
2
3
4
The aqueous solution of which of the salt has pH close to 7?
FeCl3
CH3COONa
KCN
CH3COONH4
D.
CH3COONH4
The aqueous solution of CH3COONH4 has pH close to 7 because it is a salt of weak acid and weak base.
Consider the following reactions in which all the reactants and the products are in gaseous state
2.5 × 10-3
2.5 × 103
1.0 × 10-5
5 × 103
At a certain temperature, the dissociation constants of formic acid and acetic acid are 1.8 × 10-4 and 1.8 × 10-5 respectively. The concentration of acetic acid solution in which the hydrogen ion has the same concentration as in 0.001 M formic acid solution is equal to
0.01 M
0.001 M
0.1 M
0.0001 M
What is the overall formation equilibriumconstant for the ion [ML4]2- ion, given that β4 for this complex is 2.5 × 1013?
2.5 × 1013
5 × 10-13
2.5 × 10-14
4.0 × 10-13
1.6 moles of PCl5(g) is placed in 4 dm closed vessel. When the temperature is raised to 500 K, it decomposes and at equilibrium 1.2 moles of PCl5(g) remains. What is the K, value for the decomposition of PCl5(g) to PCl3(g) and Cl5(g) at 500 K?
0.013
0.050
0.033
0.067
For a concentrated solution of a weak electrolyte AxBy of concentration 'C', the degree of dissociation 'a' is given as
α = √ Keq/ C ( x + y)
α = √ Keq/ C ( xy)
α =( Keq/ Cxy)
α =( Keq/ Cxy)