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 Multiple Choice QuestionsMultiple Choice Questions

111.

Reduction of nitrobenzene with Zn and alcoholic KOH solution results in the formation of the following compound.

  • hydrazobenzene

  • azobenzene

  • aniline

  • phenylhydroxylamine


112.

Nitrobenzene on reduction using zinc in alkaline medium results in X. The number of sigma (σ) and pi (π) bonds in X is-

  • 24 σ, 7 π

  • 24 σ, 6 π

  • 27 σ, 7 π

  • 24 σ, 6 π


113.

Identify A and B in the following reactions

 


114.

Which of the following statements is not correct?

  • The six carbons in benzene are sp2 hybridised.

  • Benzene has (4n + 2) Π electrons.

  • Benzene undergoes substitution reactions

  • Benzene has two carbon-carbon bond lengths, 1.54 Å and 1.34 Å.


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115.

The chlorination of ethane is an example for which type of the following reactions ?

  • Nucleophilic substitution

  • Electrophilic substitution

  • Free radical substitution

  • Rearrangement


116.

C2H6 450°C C2H4 + H2

Above reaction is known as

  • combustion

  • rearrangement

  • pyrolysis

  • cleavage


117.

Which one of the following gives sooty flame on combustion?

  • C2H4

  • CH4

  • C2H6

  • C6H6


118.

What is Z in the following reaction?

CH3-CH2-CO2NaNaOH/CaO Z

  • propane

  • n-butane

  • ethane

  • ethyne


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119.

Which of the following reagent is used to find out carbon-carbon multiple bonds?

  • Grignard reagent

  • Baeyer's reagent

  • Sandmeyer's reagent

  • Gatermann reagent


B.

Baeyer's reagent

Among the given options, Baeyer's reagent is used to find out carbon-carbon multiple bonds.

With the cold dilute alkaline KMnO4 (Baeyer's reagent), alkenes give 1, 2-glycols, e.g. 

CH3-CH=CH2+H2O + [O]

KMnO4KOHCH3 - CHOH - CH2OH

On reaction with Baeyer's reagent, terminal alkyne give carboxylic acids while non-terminal alkynes give diketones.

CH3-C≡CH +3[O] 298-303 KKMnO4/ KOH CH3COOH + CO2 

CH3-C≡C-CH3 + 2[O] 298-303 KKMnO4/ KOH CH3-CO-CO-CH3


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120.

Which one of the following is more readily hydrolysed by SN1 mechanism?

  • (C6H5)2C(CH3)Br

  • C6H5CH2Br

  • C6H5CH(CH3)Br

  • (C6H5)2CHBr


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