2.5 g of the carbonate of a metal was treated with 100 mL of 1N H

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 Multiple Choice QuestionsMultiple Choice Questions

331.

Assertion : The molality of the solution does not change with change in tempe-rature.

Reason : The molality is expressed in units of moles per 1000 g of solvent.

  • If both assertion and reason are true and reason is the correct explanation of assertion.

  • If both assertion and reason are true but reason is not the correct explanation of assertion.

  • If assertion is true but reason is false.

  • If both assertion and reason are false.


332.

What is the molarity of H2SO4 solution that has a density of 1.84 g/cc at 35°C and contains 98% by weight?

  • 4.18 M

  • 8.14 M

  • 18.4 M

  • 18 M


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333.

2.5 g of the carbonate of a metal was treated with 100 mL of 1N H2SO4. After the completion of the reaction, the solution was boiled off to expel CO2 and was then titrated against 1N NaOH solution. The volume of alkali that would be consumed, if the equivalent weight of the metal is 20

  • 50

  • 25

  • 75

  • 100


A.

50

Equivalent weight of metal carbonate = 20 + 30 = 50

2.5 gm of metal carbonate = 2.550 = 0.05 eq.

Number of equivalent of H2SO4 would have reacted = 0.05

Number of equivalent of H2SO4 taken = 100 × 11000= 0.1

Number of equivalent weight of H2SO4 reamins unreacted = 0.1 - 0.05 = 0.05 eq.

 Number of equivalent of alkali consumed = 0.05 eq.

milli eq = Normality × Volume in mL

1.0 × V = 0.05 × 1000

V = 0.05 × 10001.0 = 50 mL


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334.

Percentage of Se (at. mass= 78.4) in peroxidase anhydrase enzyme is 0.5% by weight, then minimum molecular mass ofperoxidase anhydrase enzyme is

  • 1.576 x 104

  • 1.576 X 103

  • 15.76

  • 2.136 X 104.


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335.

If the Vrms is 30 R1/2 at 27oC then calculate the molar mass of gas in kilogram .

  • 1 Kg

  • 2 Kg

  • 0.001 Kg

  • 0.002 Kg


336.

A unit cell of sodium chloride has four formula units. The edge length of the unit cell is 0.564 nm. What is the density of sodium chloride?

  • 1.2 g/cm3

  • 2.165g/cm3

  • 3.64 g/cm3

  • 4.56 g/cm3


337.

The vapour pressure of pure benzene at a certain temperature is 0.850 bar. A non-volatile, non-electrolyte solid weighing 0.5 g is added to 39.0 g of benzene (molar mass 78 g/mol). The vapour pressure of the solution then is 0.845 bar. What is the molecular mass of the solid substance?

  • 58

  • 180

  • 170

  • 145


338.

2.0 molar solution is obtained, when 0.5 mole solute is dissolved in :

  • 250 ml solvent

  • 250 g solvent

  • 250 ml solution

  • 1000 ml solvent


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339.

What will be the normality of a solution, containing 4.9 g. H3PO4 dissolved in 500 ml water ?

  • 0.3

  • 1.0

  • 3.0

  • 0.1


340.

Phenolphthalein is not suitable for the titration of :

  • NaOH vs (COOH)2

  • KOH vs H2SO4

  • K2CO3 vs HCl

  • none of the above


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