Which one of the following about an electron occupying the 1s orbital in a hydrogen atom is incorrect? (The Bohr radius is represented by a₀).

• The electron can be found at a distance 2a₀ from the nucleus.

• The probability density of finding the electron is maximum at the nucleus.

• The total energy of the electron is maximum when it is at a distance a₀ from the nucleus.

• The magnitude of the potential energy is double that of its kinetic energy on a an average.

Hinsberg’s reagent is:

• C₆H₅SO₂Cl

• SOCl₂

• (COCl)₂

• C₆H₅COCl

If p is the momentum of the fastest electron ejected from a metal surface after the irradiation of light having wavelength λ, then for 1.5 p momentum of the photoelectron, the wavelength of the light should be: (Assume kinetic energy of ejected photoelectron to be very high in comparison to work function) :

• $\frac{2}{3}\mathrm{\lambda }$

• $\frac{4}{9}\mathrm{\lambda }$

• $\frac{3}{4}\mathrm{\lambda }$

• $\frac{1}{2}\mathrm{\lambda }$

The degenrate orbitals of [Cr(H₂O)₆]³⁺ are

• d_yz and d_z2

• d_x2 and d_xz

• d_xz and d_yz

• ${\mathrm{d}}_{{\mathrm{x}}^2-{\mathrm{y}}^2}$and d_xy

265.

Among the following, the molecule expected to be stabilized by anion formation is: 

C₂, O₂, NO and F₂

• NO

• C₂

• F₂

• O₂

For any given series of spectral lines of atomic hydrogen, let $∆\overline{\mathrm{v}} = {\overline{\mathrm{v}}}_{\max } - {\overline{\mathrm{v}}}_{\min }$ be the difference in maximum and minimum frequencies in cm^-1. The ratio $∆{\overline{\mathrm{v}}}_{\mathrm{Balmer}}$ is:

• 4 : 1

• 9 : 4

• 5 : 4

• 27.5

The graph between Ψ² and r(radial diatance) is shown beow . This represents

• 2s orbital

• 2p orbital

• 3s orbital

• 1s orbital

The ratio of the shortest wavelength of two spectral series of hydrogen spectrum is found to be about 9. The spectral series are:

• Paschen and Pfund

• Lyman and Paschen

• Brackett and Pfund

• Balmer and Brackett

Two electrons occupying the same orbital are distinguished by

• Magnetic quantum number

• Azimuthal quantum number

• Spin quantum number

• Spin quantum number

Magnetic moment 2.84 BM is given by (At. no. Ni= 28, Ti= 22, Cr=24, Co = 27)

• Ni²⁺

• Ti³⁺

• Cr³⁺

• Cr³⁺