Which of the following arrangement is possible?
n | l | m | s |
5 | 2 | 2 | +1/2 |
2 | 2 | 0 | -1/2 |
3 | -2 | 1 | +1/2 |
0 | 0 | 1 | +1/2 |
If the mass defect of is 0.090 u , then binding energy per nucleon is :
(1 u = 931.5 MeV)
9.315 MeV
931.5 MeV
83.0 MeV
8.38 MeV
27Co60 is radioactive because :
its atomic number is high
it has high ratio
it has high ratio
None of the above
Assertion : For Balmer series of hydrogen spectrum, the value n1 = 2 and n2 = 3, 4, 5... .
Reason : The value of n2 for a line in Balmer series of hydrogen spectrum having the highest wavelength is 6.
If both assertion and reason are true and reason is the correct explanation of assertion.
If both assertion and reason are true but reason is not the correct explanation of assertion.
If assertion is true but reason is false.
If both assertion and reason are false.
C.
If assertion is true but reason is false.
The wavelength of the line can be calculated by the Rydberg formula :
( R = Rydberg constant)
Therefore, wavelength will be highest in Balmer series (n1 = 2) when n2 is 3.
In nuclear explosion, the energy is released in the form of :
kinetic energy
electrical energy
potential energy
None of these
The number of atoms in 52 g of He is
78.299 x 1024atoms
7.820 x 10-24atoms
7.829 x 1024 atoms
78.234 x 1025 atoms
Threshold frequency of a metal is 5 1013 s-1 upon which 1 x 1014s-1 frequency light is focused. Then the maximum kinetic energy of emitted electron is
3.3 10-21
3.3 10-20
6.6 10-23
6.6 10-20
From elementary molecular orbital theory we can deduce the electronic configuration of the singly positive nitrogen molecular ion as :
1s2 , 1s2 , 2s2 , 2s2 , 2p4 , 2p1
1s2 , 1s2 , 2s2 , 2s2 , 2p2 , 2p3
1s2 , 1s2 , 2s2 , 2s2 , 2p3 , 2p2
1s2 , 1s2 , 2s2 , 2s2 , 2p2 , 2p4