A magnetic moment of 1.73 BM will be shown by one among the follo

Previous Year Papers

Download Solved Question Papers Free for Offline Practice and view Solutions Online.

Test Series

Take Zigya Full and Sectional Test Series. Time it out for real assessment and get your results instantly.

Test Yourself

Practice and master your preparation for a specific topic or chapter. Check you scores at the end of the test.
Advertisement

 Multiple Choice QuestionsMultiple Choice Questions

321.

The electronic configuration of Cu is

  • [Ne] 3s2, 3p6, 3d9, 4s2

  • [Ne] 3s2, 3p6, 3d10, 4s1

  • [Ne] 3s2, 3p6, 3d3, 3d9, 4s2, 4p6

  • [Ne] 3s2, 3p6, 3d5, 4s2, 4p4


322.

Assertion: Cuprous ion (Cu+) is colorless whereas cupric ion (Cu2+) is blue in the aqueous solution.
Reason: Cuprous ion (Cu+) has unpaired electrons while cupric ion (Cu2+) does not.

  • If both assertion and reason are true and reason is a correct explanation of the assertion.

  • If both the assertion and reason are true but the reason is not a correct explanation of the assertion.

  • If the assertion is true but the reason is false.

  • If both the assertion and reason are false.


323.

The stable bivalency of Pb and trivalencey of Bi is:

  • due to d contraction in Pb and Bi

  • due to relativistic contraction of the 6s orbitals of Pb and Bi, leading to inert pair effect

  • due to screening effect

  • due to the attainment of noble liquid configuration


Advertisement

324.

A magnetic moment of 1.73 BM will be shown by one among the following

  • [Cu(NH3)4]2+

  • [Ni(CN)4]2-

  • TiCl4

  • [CoCl6]4-


A.

[Cu(NH3)4]2+

Magnetic moment, μ is related with number of unpaired electrons as 

                      μ= nn+2 BM1.732= n(n+2)

On solving n =1

Thus, the complex/compound having one unpaired electron exhibit a magnetic moment of 1.73 BM.

(a) In [Cu(NH3)4]2+

      Cu2+ = [Ar] 3d9

         

(Although in the presence of strong field ligand NH3, the unpaired electron gets excited to higher energy level but it still remains unpaired).

(b) In [Ni(CN)4]2-

       Ni2+= [Ar]3d8

         

But CN- being strong field ligand pair up the unpaired electrons and hence in this complex, number of unpaired electrons = 0.

(c) In [TiCl4]

       Ti4+= [Ar] 3d7

(d) In [CoCl6]4-

     Co2+ = [Ar] 3d7

     

It contains three unpaired electrons.
Thus, [Cu(NH3)4]2+ is the complex that exhibits a magnetic moment 1.73 BM.


Advertisement
Advertisement
325.

Which of the following does not give oxygen on heating?

  • KClO3

  • Zn(ClO3)2

  • K2Cr2O7

  • (NH4)2Cr2O7


326.

Which ofthe following lanthanoid ions is diamagnetic?
(At. nos. Ce = 58, Sm = 62, Eu = 63, Yb= 70)

  • Ce2+

  • Sm2+

  • Eu2+

  • Yb2+


327.

Platinum, palladium and iridium are called noble metals because:

  • Alfred Nobel discovered them

  • they are shining lustrous and pleasing to look at

  • they are found in native state

  • they are inert towards many common reagents


328.

Cupric compounds are more stable than their cuprous counterparts in solid state. This is because

  • the endothermic character of the 2nd IP of Cu is not so high

  • size of Cu2+ is less than Cu+

  • Cu2+ has stable electronic configuration as compared to Cu+

  • the lattice energy released for cupric compounds is much higher than Cu+


Advertisement

 Multiple Choice QuestionsShort Answer Type

329.

Explain briefly the cause of Lanthanoid contraction.


 Multiple Choice QuestionsMultiple Choice Questions

330.

Anhydrous ferric chloride is prepared by:

  • dissoving Fe(OH)3 in concentrated HCl

  • dissolving Fe(OH)3 in dilute HCl

  • passing dry HCl overheated iron scrap

  • passing dry Cl2 gas overheated iron scrap


Advertisement