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The p-Block Elements

Multiple Choice Questions

531.

Ammonia on reaction with chlorine forms an explosive NCl₃. What is themole ratio of NH₃ and Cl₂ required for this reaction?

8:3
1:1
1:3
10:1

532.

Xenon reacts with fluorine at 873 Kand 7 bar to form XeF₄. It his reaction, the ratio of xenon and fluorine required is

1:5
10:1
1:3
5:1

533.

X reacts with dilute nitric acid to form 'laughing gas'. What is X ?

Cu
P₄
S₈
Zn

534.
In Haber's process, 50.0 g of N₂(g) and 10.0 g of H₂(g) are mixed to produce NH₃ (g). What is the number of moles of NH₃ (g) formed?

3.33

2.36

2.01

5.36

3.33

$The reaction proceeds as : N_{2} + 3 H_{2} ⇋ 2 {NH}_{3} 28 g 6 g 34 g 6 g H_{2} reacts with 28 g N_{2} Therefore 10 g H_{2} reacts with \frac{28}{6} \times 10 = 46.67 g N_{2} . i . e H_{2} is limiting reagents and N_{2} is in excess . Now, 6 g H_{2} produced 34 g {NH}_{3} therefore 10 g H_{2} produced (\frac{34}{6} \times 10) g {NH}_{3} Therefore, we can calculate number of moles of {NH}_{3} as {}^{n}{NH}_{3} = \frac{Produced weight}{Molecular weight} = \frac{(\frac{34}{6} \times 10)}{17} = \frac{34}{6} \times \frac{10}{17} = \frac{10}{3} = 3.33$