Born-Haber cycle may be used to calculate
electronegativity
mass number
oxidation number
electron affinity
The heat of formation for CO2 (g), H2O (l) and CH4 (g) are -400 kJ mol-1, -280 kJ mol-1 and -70 kJ mol-1 respectively. The heat of combustion of CH4 in kJ mol-1 is
890
-160
-890
-90
C (s) + O2 (g) → CO2 (g); H = -94kcal
2CO (g) + O2 (g) → 2CO2 (g); H = -135 kcal.
The heat of formation of CO (g) is
-26.4 kcal
41.2 kcal
26.4 kcal
229.2 kcal
The entropy of a perfectly crystalline material is zero at 0°C. This is statement of
first law of thermodynamics
second law of thermodynamics
third law of thermodynamics
law of conservation of energy
C.
third law of thermodynamics
(a) First law of thermodynamics states that energy can neither be created nor be destroyed but one form of energy can be converted into another.
(b) Second law of thermodynamics states that for a spontaneous process in an isolated
system, the change in entropy is positive.
(c) Third law ofthermodynamics states that the entropy of a perfectly crystalline substance is zero at 0°C.
(d) Law of conservation of energy states that energy can neither be created nor be destroyed.
Hence, the given statement is third law of thermodynamics.
In any chemical reaction, a quantity that decrease to a minimum is
free energy
entropy
temperature
enthalpy
Given, H2O (l) → H2O (g); H1 = +43 kJ
H2O (s) → H2O (l); H2 = +6.05 kJ. Calculate the enthalpy of sublimation of ice.
49.75 kJ mol-1
37.65 kJ mol-1
43.7 kJ mol-1
55.23 kJ mol-1
If standard enthalpies of formation of CaCl (s) (hypothetical) and that of CaCl2 (s) are -188 J mol-1 and -795 kJ mol-1 respectively, calculate the value of standard heat of reaction for the following disproportionation reaction
2CaCl (s) → CaCl2 (s) + Ca (s)
-607 kJ mol-1
+607 kJ mol-1
-419 kJ mol-1
+419 kJ mol-1
Heat formation of H2O is -188 kJ/ mol and H2O2 is 286 kJ/mol. The enthalpy change for the reaction; 2H2O2 → 2H2O + O2 is
196 kJ
-196 kJ
984 kJ
-984 kJ
When 1 mole of a gas is heated at constant volume, temperature is raised from 298 K to 308 K. Heat supplied to the gas is 500J. Then, which statement is correct?
q= -W = 500J : ΔE= 0
q= W = 500J : ΔE= 0
q = ΔE= 500J , W= 0
ΔE = 0; q= W = -500J
If enthaplies of formation for C2H2(g), CO2(g) and H2O(l) at 25°C and 1atm pressure be 52, -394 and -286kJ mol-1 respectively, then the enthaply of combustion of C2H4(g) will be
-141.2 kJ mol-1
-1412 kJ mol-1
+ 141.2 kJ mol-1
+ 1412 kJ mol-1