Which thermodynamic parameter is not a state function?
q at constant pressure
q at constant volume
W at adiabatic
W at isothermal
Assertion: For an isolated system, q is zero.
Reason : In an isolated system, change in U and V is zero.
If both assertion and reason are true and reason is the correct explanation of assertion.
If both assertion and reason are true but reason is not the correct explanation of assertion.
If assertion is true but reason is false.
If both assertion and reason are false.
Assertion : Entropy of system increases for a spontaneous reaction.
Reason : Enthalpy of reaction always decreases for spontaneous reaction.
If both assertion and reason are true and reason is the correct explanation of assertion.
If both assertion and reason are true but reason is not the correct explanation of assertion.
If assertion is true but reason is false.
If both assertion and reason are false.
Assertion : Catalyst changes Gibbs free energy of system.
Reason : Catalyst changes pre-exponential factor of a chemical reaction.
If both assertion and reason are true and reason is the correct explanation of assertion.
If both assertion and reason are true but reason is not the correct explanation of assertion.
If assertion is true but reason is false.
If both assertion and reason are false.
Assertion : A process is called adiabatic if the system does not exchange heat with the surroundings.
Reason : It does not not involve increase or decrease in temperature of the system.
If both assertion and reason are true and reason is the correct explanation of assertion
If both assertion and reason are true but reason is not the correct explanation of assertion.
If assertion is true but reason is false.
If both assertion and reason are false.
Heat of combustion of C and CO are -394 and -285 kJ respectively , so heat of formation of CO in kJ/mol is :
- 218
- 109
+ 109
+ 218
The enthalpy of formation of CO(g), CO2(g), N2O(g), and N2O4(g) is -110, -393, +811 and 10 kJ/mol respectively. For the reaction, N2O4 + 3CO(g) N2O(g)+ 3CO2(g); Hr (kJ/mol) is
-212
+212
+48
-48
The difference between heat of reaction at constant pressure and constant volume of the reaction :
2C6H6 (l) + 15O2 (g) 12CO2 + 6H2O (l)
at 25°C (in kJ) is :
- 7.43
3.72
- 3.72
7.43
For which reaction will H - E = 0 ? Assume that each reaction is carried out in an open container .
2CO2 (g) + O2 (g) 2CO2 (g)
PCl5 (g) PCl3 (g) + Cl2 (g)
H2 (g) + Br2 (g) 2HBr (g)
C (s) + 2H2O (g) 2H2 (g) + CO2 (g)
C.
H2 (g) + Br2 (g) 2HBr (g)
H = E + ngRT
For reaction H2 (g) + Br2 (g) 2HBr (g)
ng = 0 , while for other ng 0
Thus , H = E + 0 x RT
H - E = 0