The area (in square units) bounded by the curves y =Â Â 2y-x+3 =0, X -axis and lying in the first quadrant isÂ
9
36
18
18
The intercepts on X- axis made by tangents to the curve,  which are parallel to the line y =2x, are equal to
±1
±2
±3
±3
Let I be the purchase value of an equipment and V(t) be the value after it has been used for t years. The value V(t) depreciates at a rate given by differential equationd V(t)/dt = - k(T - t), where k > 0 is a constant and T is the total life in years of the equipment. Then the scrap value V(T) of the equipment is
For x ∈, (0, 5π/2) define f(x). Then f (x) =  has
local maximum at π and 2π.
local minimum at π and 2π
local minimum at π and the local maximum at 2π.
local minimum at π and the local maximum at 2π.
The area of the region enclosed by the curves y = x, x = e, y =1/x and the positive x-axis is
1/2Â square units
1 square units
3/2 square units
3/2 square units
The area bounded by the curve y = cos x and y = sin x between the ordinates x = 0 and x = 3Ï€/2 isÂ
Solution of the differential equation
cos x dy = y (sin x - y) dx, 0 < x < π/2, isÂ
sec x = (tan x + C ) yÂ
 y sec x = tan x + C
 y tan x = sec x + CÂ
 y tan x = sec x + CÂ
The area (in sq. units) of the region
{(x, y} : x  ≥ 0, x + y ≤ 3, x2 ≥ 4y and y ≤ 1 +√x}
5/2
59/12
3/2
3/2
The area of the region bounded by the parabola (y – 2)2 = x – 1, the tangent to the parabola at the point (2, 3) and the x-axis isÂ
3
6
9
9
C.
9
Equation of tangent at (2, 3)Â
≡ x – 2y + 4 = 0
Required Area
The area of the plane region bounded by the curves x + 2y2= 0 and x + 3y2= 1 is equal toÂ
5/3
1/3
2/3
2/3