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Conic Section

Multiple Choice Questions

71.

If y = 4x + 3 is parallel to a tangent to the parabola y² = 12x, then its distance from the normal parallel to the given line is

$\frac{213}{\sqrt{17}}$
$\frac{219}{\sqrt{17}}$
$\frac{211}{\sqrt{17}}$
$\frac{210}{\sqrt{17}}$

72.

Let the equation of an ellipse be $\frac{x^{2}}{144} + \frac{y^{2}}{25} = 1$ . Then, the radius of the circle with centre (0, $\sqrt{2}$ ) and passing through the foci of the ellipse is

73.

The value of $λ$ for which the curve (7x + 5)² + (7y + 3)² = $λ^{2}$ (4x + 3y - 24)²represents a parabola is

$\pm \frac{6}{5}$
$\pm \frac{7}{5}$
$\pm \frac{1}{5}$
$\pm \frac{2}{5}$

74.

The equation of the common tangent with positive slope to the parabola y² = 8 $\sqrt{3}$ x and the hyperbola 4x² - y² = 4 is

$y = \sqrt{6} x + \sqrt{2}$
$y = \sqrt{6} x - \sqrt{2}$
$y = \sqrt{3} x + \sqrt{2}$
$y = \sqrt{3} x - \sqrt{2}$

75.

The point on the parabola y² = 64x which is nearest to the line 4x + 3y + 35 = 0 has coordinates

(9, - 24)
(1, 81)
(4, - 16)
(- 9, - 24)

76.

Let z₁, z₂ be two fixed complex numbers in the argand plane and z be an arbitrary point satisfying $|z - z_{1}| + |z - z_{2}| = 2 |z_{1} - z_{2}|$ Then, the locus of z will be

an ellipse
a straight line joining z₁ and z₂
a parabola
a bisector of the line segment joining z₁ and z₂

77.

Let z, be a fixed point on the circle of radius 1 centered at the origin in the Argand plane and $z_{1} \neq \pm 1$ . Consider an equilateral triangle inscribed in the circle with z₁, z₂, z₃ as the vertices taken in the counterclockwise direction. Then, z₁z₂z₃ is equal to

z₁²
z₁³
z₁⁴
z₁

78.
The equation of hyperbola whose coordinates of the foci are (± 8, 0) and the length of latusrectum is 24 units, is

3x² - y² = 48

4x² - y² = 48

x² - 3y² = 48

x² - 4y² = 48

3x² - y² = 48

Let equation of hyperbola be

$\frac{x^{2}}{a^{2}} - \frac{y^{2}}{b^{2}} = 1 . . . (i) Given, foci, (\pm 8, 0) = (\pm ae, 0) \Rightarrow ae = 8 . . . (ii) and length of latusrectum = \frac{2 b^{2}}{a} ∴ 24 = \frac{2 b^{2}}{a} \Rightarrow b^{2} = 12 a . . . (iii)$

$∴ From Eq . (ii), a^{2} e^{2} = 64 \Rightarrow a^{2} (\frac{a^{2} + b^{2}}{a^{2}}) = 64 \Rightarrow a^{2} + b^{2} = 64 \Rightarrow a^{2} + 12 a = 64 [∵ From Eq . (iii)] \Rightarrow a^{2} + 16 a - 4 a - 64 = 0 \Rightarrow a (a + 16) - 4 (a + 16) = 0 \Rightarrow a = - 16 or a = a ∴ a = 4 [∵ a cannot be negative]$

On putting a= 4 in Eq. (iii), we get

$b^{2} = 12 \times 4 \Rightarrow b^{2} = 48 ∴ From Eq . (i), \frac{x^{2}}{16} - \frac{y^{2}}{48} = 1 \Rightarrow 3 x^{2} - y^{2} = 48$

79.

If the circle x² + y² + 2gx + 2fy + c = 0 cuts the three circles x² + y² - 5 = 0, x² + y² - 8x - 6y + 10 = 0 and x² + y² - 4x + 2y - 2 = 0 at the extremities of their diameters, then