If 2x + y + k = 0 is a normal to the parabola y2 = - 8x, then the

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 Multiple Choice QuestionsMultiple Choice Questions

181.

If x2a2 + y2b2 = 1 a > b and x2 - y2 = c2 cut at right angles, then

  • a2 + b2 = 2c2

  • b2 - a2 = 2c2

  • a2 - b2 = 2c2

  • a2b2 = 2c2


182.

The equation of the conic with focus at (1, - 1) directrix along x - y + 1 = 0 and with eccentricity 2, is

  • x2 - y2 = 1

  • xy = 1

  • 2xy - 4x + 4y + 1 = 0

  • 2xy + 4x - 4y - 1 = 0


183.

The number of common tangents to the circles x2 + y2 = 4 and x2 + y2 - 6x - 8y = 24 is

  • 0

  • 1

  • 3

  • 4


184.

The locus of the mid-points of the focal chord of the parabola y2 = 4ax is

  • y2 = a(x - a)

  • y2 = 2a(x - a)

  • y2 = 4a(x - a)

  • None of these


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185.

A rod of length l slides with its ends on two perpendicular lines. Then, the locus of its mid point is

  • x2 + y2 = l24

  • x2 + y2 = l22

  • x2 - y2 = l24

  • None of these


186.

The line joining (5, 0) to (10cosθ, 10sinθ) is divided internally in the ratio 2 : 3 at P. If 0 varies, then the locus of P is

  • a straight line

  • a pair of straight lines

  • a circle

  • None of the above


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187.

If 2x + y + k = 0 is a normal to the parabola y2 = - 8x, then the value of k, is

  • 8

  • 16

  • 24

  • 32


C.

24

The equation of any normal to the parabola

y2 = - 8x is y = mx + 4m + 2m3       ... (i)

 using equation of normal of parabola in slope form y = mx - 2am - am3 and a = - 2]

But, the given normal is

2x + y + k = 0

         y = - 2x - k     ...(ii)

Comparing Eqs. (i) and (ii), we get

                       m = - 2

and - 4m - 2m3 = k

   k = 8 + 16 = 24

 


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188.

If the equation of an ellipse is 3x2 + 2y2 + 6x - 8y + 5 = 0, then which of the following are true?

  • e = 13

  • centre is (- 1, 2)

  • foci are (- 1, 1) are (- 1, 3)

  • All of the above


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189.

The equation of the common tangents to the two hyperbolas x2a2 - y2b2 = 1 and y2a2 - x2b2 = 1, are

  • y = ± x ± b2 - a2

  • y = ± x ± a2 - b2

  • y = ± x ± a2 + b2

  • y = ± x ± a2 - b2


190.

The equation of sphere concentric with the sphere x2 + y2 + z2 - 4x - 6y - 8z - 5 = 0 and which passes through the origin, is

  • x2 + y2 + z2 - 4x - 6y - 8z = 0

  • x2 + y2 + z2 - 6y - 8z = 0

  • x2 + y2 + z2 = 0

  • x2 + y2 + z2 - 4x - 6y - 8z - 6 = 0


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