If P1, P2, P3 are the perimeters of the three circles
x2 + y2 + 8x - 6y = 0, 4x2 + 4y - 4x - 12y - 186 = 0 and x2 + y - 6x + 6y - 9 = 0 respectively, then
If the line 3x - 2y + 6 = 0 meets X-axis and Y-axis, respectively at A and B, then the equation of the circle with radius AB and centre at A is
x2 + y2 + 4x + 9 = 0
x2 + y2 + 4x - 9 = 0
x2 + y2 + 4x + 4 = 0
x2 + y2 + 4x - 4 = 0
A line l meets the circle x2 + y2 = 61 in A, B and P(- 5, 6) is such that PA = PB = 10. Then,the equation of l is
5x + 6y + 11 = 0
5x - 6y - 11 = 0
5x - 6y + 11 = 0
5x - 6y + 11 = 0
If (1, a), (b, 2) are conjugate points with respect to the circle x2 + y2 = 25, then 4a + 2b is equal to
25
50
100
150
The radius of the circle r = is
1
2
3
4
A.
1
The equation of the circle whose diameter is the common chord of the circles x2 + y2 + 2x + 3y + 2 = 0 and x2 + y2 + 2x - 3y - 4 = 0 is
x2 + y2 + 2x + 2y + 2 = 0
x2 + y2 + 2x + 2y - 1 = 0
x2 + y2 + 2x + 2y + 1 = 0
x2 + y2 + 2x + 2y + 3 = 0
If x - y + 1 = 0 meets the circlex2 + y2 + y - 1 = 0 at A and B, then the equation of the circle with AB as diameter is
2(x2 + y2) + 3x - y + 1 = 0
2 (x2 + y2) + 3x - y + 2 = 0
2(x2 + y2) + 3x - y + 3 = 0
x2 + y2 + 3x - y + 1 = 0