If the function f(x) = is continuous in the interval (- , 6), then the values of a and b are respectively
0, 2
1, 1
2, 0
2, 1
The value of m for which the function f(x) = , is differentiable at x = 1, is
0
1
2
does not exist
If y = (1 + x1/4)(1 + x1/2)(1 - x1/4), then dy/dx is equal to
1
- 1
x
B.
- 1
For the function f(x) = x2 - 6x + 8, , the value of x for which f'(x) vanishes, is
9/4
5/2
3
7/2